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Metals - Uses of metals

Grade 11IGCSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Aluminum (AlAl) is widely used in aircraft manufacture because of its low density and its strength when alloyed. It is also used in food containers because of its resistance to corrosion caused by a protective layer of aluminum oxide, Al2O3Al_2O_3.

Copper (CuCu) is utilized for electrical wiring due to its high electrical conductivity and ductility. It is also used in cooking utensils because it is an excellent thermal conductor and is relatively unreactive.

Iron (FeFe) is extracted and primarily used to create steel alloys. Pure iron is relatively soft and easily corroded, so it is rarely used alone for structural purposes.

Mild Steel (containing approximately 0.25%0.25\% carbon) is used for car bodies and machinery because it is strong, tough, and malleable.

High-carbon Steel (containing approximately 0.5%0.5\% to 1.4%1.4\% carbon) is harder and more brittle, making it ideal for cutting tools and masonry nails.

Stainless Steel is an alloy of iron containing Chromium (CrCr) and Nickel (NiNi). It is used for cutlery and surgical instruments because the CrCr forms a protective oxide layer that prevents rusting.

Zinc (ZnZn) is used for galvanizing (coating iron or steel) to prevent rusting through sacrificial protection, and in the production of the alloy brass (CuCu and ZnZn).

📐Formulae

4Al(s)+3O2(g)2Al2O3(s)4Al(s) + 3O_2(g) \rightarrow 2Al_2O_3(s)

Density (ρ)=mass (m)volume (V)\text{Density } (\rho) = \frac{\text{mass } (m)}{\text{volume } (V)}

Zn(s)Zn2+(aq)+2eZn(s) \rightarrow Zn^{2+}(aq) + 2e^-

Brass=Cu+Zn\text{Brass} = Cu + Zn

Stainless Steel=Fe+Cr+Ni\text{Stainless Steel} = Fe + Cr + Ni

💡Examples

Problem 1:

Explain why Aluminum (AlAl) is preferred over Copper (CuCu) for overhead power cables, even though Copper is a better electrical conductor.

Solution:

Aluminum has a much lower density than Copper (2.7 g/cm32.7 \text{ g/cm}^3 vs 8.9 g/cm38.9 \text{ g/cm}^3).

Explanation:

Because overhead cables must span long distances, using AlAl reduces the weight load on the supporting pylons. Additionally, AlAl is cheaper than CuCu and develops a protective Al2O3Al_2O_3 layer that prevents atmospheric corrosion.

Problem 2:

A manufacturer wants to create a bridge that resists rusting in a coastal environment. Which alloy of Iron (FeFe) should be used, and why?

Solution:

Stainless Steel (alloyed with CrCr and NiNi).

Explanation:

Standard mild steel reacts with oxygen and water to form rust (Fe2O3nH2OFe_2O_3 \cdot nH_2O). In stainless steel, the Chromium (CrCr) reacts with oxygen to form a thin, invisible, and stable layer of Chromium Oxide (Cr2O3Cr_2O_3) on the surface, which blocks further oxygen from reaching the Iron.

Problem 3:

How does Zinc (ZnZn) protect an Iron (FeFe) pipe through 'galvanization'?

Solution:

Zinc acts as a sacrificial anode because it is more reactive than Iron.

Explanation:

In the presence of oxygen and water, the Zinc will oxidize preferentially according to the half-equation ZnZn2++2eZn \rightarrow Zn^{2+} + 2e^-. Even if the ZnZn coating is scratched, the ZnZn continues to protect the FeFe by providing electrons that prevent the FeFe from forming Fe2+Fe^{2+} ions.

Uses of metals - Revision Notes & Key Formulas | IGCSE Grade 11 Chemistry