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Metals - Alloys

Grade 11IGCSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

An alloy is a mixture of a metal with one or more other elements, which can be other metals or non-metals like Carbon (CC).

In a pure metal, atoms are of the same size and are arranged in a regular lattice. These layers of atoms can easily slide over each other when a force is applied, making pure metals relatively soft and malleable.

Alloys are harder and stronger than pure metals because the different-sized atoms of the added element(s) disrupt the regular arrangement of the metal lattice.

The disruption of the lattice prevents the layers of atoms from sliding over each other easily, which increases the material's resistance to deformation.

Brass is an alloy made of Copper (CuCu) and Zinc (ZnZn). It is harder than pure copper and is used in musical instruments and electrical plug pins.

Bronze is an alloy of Copper (CuCu) and Tin (SnSn). It is used in making statues and ornaments due to its durability and resistance to corrosion.

Stainless steel is an alloy of Iron (FeFe), Chromium (CrCr), and Nickel (NiNi). The Chromium forms a thin, invisible layer of Chromium(III) oxide (Cr2O3Cr_2O_3) that prevents the iron from rusting.

📐Formulae

Steel=Fe+C\text{Steel} = Fe + C

Stainless Steel=Fe+Cr+Ni\text{Stainless Steel} = Fe + Cr + Ni

Brass=Cu+Zn\text{Brass} = Cu + Zn

Bronze=Cu+Sn\text{Bronze} = Cu + Sn

Composition %=Mass of alloying elementTotal mass of alloy×100\text{Composition \%} = \frac{\text{Mass of alloying element}}{\text{Total mass of alloy}} \times 100

💡Examples

Problem 1:

Explain why pure gold (2424-carat) is not typically used for making jewelry, whereas 1818-carat gold (75%Au75\% Au and 25%Ag25\% Ag or CuCu) is commonly used.

Solution:

Pure gold is too soft because its atoms are arranged in regular layers that slide easily. 1818-carat gold is an alloy.

Explanation:

In 1818-carat gold, the atoms of Silver (AgAg) or Copper (CuCu) have different sizes compared to Gold (AuAu). These atoms disrupt the regular lattice layers of the gold, making it harder for the layers to slide, thus making the jewelry more durable and resistant to wear.

Problem 2:

Determine the mass of Chromium (CrCr) required to produce 500 kg500\text{ kg} of stainless steel if the alloy must contain 18%Cr18\% Cr by mass.

Solution:

Mass of Cr=500×0.18=90 kgCr = 500 \times 0.18 = 90\text{ kg}.

Explanation:

Using the percentage composition formula: Mass of Cr=18100×500 kg=90 kg\text{Mass of } Cr = \frac{18}{100} \times 500\text{ kg} = 90\text{ kg}. This amount of Chromium ensures the formation of the protective oxide layer.

Alloys - Revision Notes & Key Formulas | IGCSE Grade 11 Chemistry