Acids, Bases and Salts - Identification of ions and gases (Qualitative analysis)
Review the key concepts, formulae, and examples before starting your quiz.
πConcepts
Qualitative analysis is used to identify the presence of specific ions (cations and anions) and gases in a sample using characteristic chemical reactions and physical observations.
Flame Tests for Cations: Used to identify metal ions by the color they impart to a Bunsen burner flame. is red, is yellow, is lilac, is orange-red, is blue-green, and is light green.
Cation identification with Aqueous and : Many metal ions form insoluble hydroxides. forms a blue precipitate; forms a green precipitate; forms a reddish-brown precipitate. , , and all form white precipitates with , but only and precipitates dissolve in excess . Only precipitate dissolves in excess .
Anion Identification: Carbonates () react with dilute acids to produce . Halides (, , ) are identified using silver nitrate () in the presence of nitric acid (), forming white (), cream (), and yellow () precipitates respectively. Sulfates () are identified using barium nitrate or barium chloride, forming a white precipitate of .
Identification of Gases: is identified by a 'squeaky pop' with a lighted splint; relights a glowing splint; turns limewater () milky; bleaches damp litmus paper; turns damp red litmus paper blue; turns acidified aqueous potassium manganate(VII) from purple to colorless.
πFormulae
(General equation for hydroxide precipitation)
(Carbonate test)
(where is a halide ion)
(Sulfate test)
(Limewater test)
π‘Examples
Problem 1:
A student is given an unknown salt solution. Adding aqueous produces a green precipitate that is insoluble in excess. Adding dilute followed by produces a white precipitate. Identify the salt.
Solution:
The salt is Iron(II) chloride ().
Explanation:
The green precipitate with indicates the presence of ions. The white precipitate formed with silver nitrate in acidic conditions indicates the presence of chloride ions (). Thus, the salt is .
Problem 2:
Describe the test to distinguish between and ions in solution.
Solution:
Add excess aqueous ammonia () to the solution.
Explanation:
Both and form a white precipitate ( and respectively) when a small amount of is added. However, only the precipitate dissolves in excess to form a colorless solution, while the precipitate remains insoluble.
Problem 3:
Identify the gas produced when dilute is added to a solid sample, given that the gas turns acidified aqueous potassium manganate(VII) from purple to colorless.
Solution:
The gas is sulfur dioxide ().
Explanation:
The reduction of purple ions to colorless ions is a specific test for reducing agents like . This suggests the original solid contained sulfite ions ().