Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Lithium () and Beryllium () are the first elements of Group 1 and Group 2 respectively, and they exhibit properties that differ significantly from the rest of their groups due to their exceptionally small atomic and ionic sizes.
The anomalous behavior is attributed to: (i) Small size of atom and ion, (ii) High electronegativity and high ionization enthalpy, (iii) High polarizing power (Charge/Radius ratio), and (iv) Absence of -orbitals in their valence shell.
Lithium's polarizing power is high, leading to a significant covalent character in its compounds (e.g., is soluble in organic solvents).
Lithium is the only alkali metal which reacts directly with nitrogen to form a nitride: .
Lithium carbonate () and lithium nitrate () are thermally unstable; decomposes to give , , and , while other alkali metal nitrates give nitrites and .
Beryllium forms compounds that are largely covalent, such as which has a polymeric chain structure in the solid state.
Beryllium oxide () and beryllium hydroxide () are amphoteric, reacting with both acids and bases, whereas oxides/hydroxides of other Group 2 elements are basic.
Diagonal Relationship: Lithium shows similarities with Magnesium () of Group 2, and Beryllium shows similarities with Aluminum () of Group 13 due to similar ionic sizes and charge/radius ratios.
The maximum coordination number for is 4 due to the presence of only four available orbitals (one and three ), whereas other members can have higher coordination numbers using -orbitals.
📐Formulae
💡Examples
Problem 1:
Explain why is soluble in organic solvents like ethanol, whereas is not.
Solution:
Due to the very small size of the ion, it has high polarizing power. This leads to a high degree of covalent character in the bond (Fajans' Rules). , having a larger ion, is predominantly ionic. Since 'like dissolves like', the covalent dissolves in organic (covalent) solvents.
Explanation:
Covalent character in ionic compounds is determined by the polarization of the anion by the cation.
Problem 2:
Write the chemical equations for the reaction of with and .
Solution:
Explanation:
These reactions demonstrate the amphoteric nature of Beryllium oxide, as it reacts with both a strong acid () and a strong base ().
Problem 3:
Compare the thermal stability of and .
Solution:
decomposes on heating: . is thermally stable and does not decompose at moderate temperatures.
Explanation:
The ion is very small and polarizes the large ion, weakening the bond and making it easier to form the more stable lattice.