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p-Block Elements - Group 14 Elements (Carbon Family)

Grade 11ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Group 14 elements, known as the Carbon Family, include Carbon (CC), Silicon (SiSi), Germanium (GeGe), Tin (SnSn), and Lead (PbPb).

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The general valence shell electronic configuration is ns2np2ns^2 np^2.

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Atomic radii increase down the group due to the addition of new energy shells, though the increase from SiSi to PbPb is small due to poor shielding by dd and ff electrons.

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Ionization Enthalpy decreases down the group. However, a slight increase is observed from SnSn to PbPb due to the poor shielding effect of 4f4f electrons.

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Carbon shows an anomalous behavior due to its small size, high electronegativity, and the absence of vacant dd-orbitals.

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Catenation is the self-linking property of atoms to form long chains or rings. Carbon exhibits the maximum catenation power in the group: C≫Si>Geβ‰ˆSn>PbC \gg Si > Ge \approx Sn > Pb.

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Carbon has three main allotropes: Diamond (sp3sp^3 hybridized, tetrahedral), Graphite (sp2sp^2 hybridized, layered structure), and Fullerenes (sp2sp^2 hybridized, cage-like molecules like C60C_{60}).

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Oxidation states: These elements show +4+4 and +2+2 oxidation states. The stability of the +2+2 oxidation state increases down the group due to the 'Inert Pair Effect', making Pb2+Pb^{2+} more stable than Pb4+Pb^{4+}.

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Carbon Monoxide (COCO) is a neutral oxide and a powerful reducing agent, while Carbon Dioxide (CO2CO_2) is an acidic oxide.

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SiCl4SiCl_4 undergoes hydrolysis because Silicon has vacant dd-orbitals to accept lone pairs from water, whereas CCl4CCl_4 does not.

πŸ“Formulae

ns2np2ns^2 np^2

SiCl4+4H2O→Si(OH)4+4HClSiCl_4 + 4H_2O \rightarrow Si(OH)_4 + 4HCl

CO + rac{1}{2}O_2 \rightarrow CO_2 \quad (\Delta H = -283 \text{ kJ mol}^{-1})

PbO2+4HCl→PbCl2+Cl2+2H2OPbO_2 + 4HCl \rightarrow PbCl_2 + Cl_2 + 2H_2O

SiO2+2NaOH→Na2SiO3+H2OSiO_2 + 2NaOH \rightarrow Na_2SiO_3 + H_2O

πŸ’‘Examples

Problem 1:

Why is PbCl4PbCl_4 a powerful oxidizing agent?

Solution:

Pb4+Pb^{4+} is less stable than Pb2+Pb^{2+} due to the inert pair effect.

Explanation:

In Lead (PbPb), the 6s26s^2 electrons are strongly held by the nucleus and do not easily participate in bonding (Inert Pair Effect). Therefore, PbPb prefers the +2+2 state over the +4+4 state. PbCl4PbCl_4 (where PbPb is +4+4) readily gains two electrons to reduce to Pb2+Pb^{2+}, making it a strong oxidizing agent.

Problem 2:

Explain why Graphite conducts electricity while Diamond does not.

Solution:

Graphite has delocalized electrons, whereas Diamond has all electrons localized in Cβˆ’CC-C Οƒ\sigma-bonds.

Explanation:

In Diamond, each carbon atom is sp3sp^3 hybridized and forms four strong Οƒ\sigma bonds with neighboring carbons, leaving no free electrons. In Graphite, each carbon is sp2sp^2 hybridized, forming three Οƒ\sigma bonds. The fourth valence electron is in a pp-orbital and is delocalized over the whole sheet, allowing for electrical conductivity.

Problem 3:

What happens when COCO is inhaled?

Solution:

It forms Carboxyhaemoglobin: Hb+CO→HbCOHb + CO \rightarrow HbCO.

Explanation:

Carbon monoxide (COCO) has a much higher affinity for haemoglobin (about 300 times) than oxygen. It forms a stable complex called carboxyhaemoglobin, which prevents haemoglobin from carrying oxygen to body tissues, eventually leading to asphyxiation.

Group 14 Elements (Carbon Family) Revision - Class 11 Chemistry ICSE