krit.club logo

Hydrogen - Position of Hydrogen in Periodic Table

Grade 11ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Hydrogen is the first element in the periodic table with the electronic configuration 1s11s^1.

It exhibits a dual nature, showing similarities to both Alkali Metals (Group 1) and Halogens (Group 17).

Resemblance with Alkali Metals: Like LiLi, NaNa, and KK, Hydrogen has one electron in its outermost shell and can form a unipositive ion H+H^+.

Resemblance with Halogens: Like FF, ClCl, and BrBr, Hydrogen is one electron short of the nearest noble gas configuration (HeHe) and can form a uninegative ion HH^-.

Diatomic Nature: Hydrogen exists as a diatomic molecule H2H_2, similar to halogens like Cl2Cl_2.

Anomalous Nature of H+H^+: The loss of an electron from a hydrogen atom results in a nucleus (proton) of extremely small size (approx 1.5×103 pm1.5 \times 10^{-3} \text{ pm}), which does not exist freely and associates with water to form H3O+H_3O^+.

Ionization Enthalpy: The ionization enthalpy of Hydrogen (1312 kJ mol11312 \text{ kJ mol}^{-1}) is much higher than that of alkali metals and is comparable to halogens (e.g., Fluorine is 1681 kJ mol11681 \text{ kJ mol}^{-1}).

📐Formulae

HH++eH \rightarrow H^+ + e^-

H+eHH + e^- \rightarrow H^-

H++H2OH3O+H^+ + H_2O \rightarrow H_3O^+

2Na+H22NaH2Na + H_2 \rightarrow 2NaH

H2+Cl22HClH_2 + Cl_2 \rightarrow 2HCl

Xns1 (General Configuration for Group 1 and Hydrogen)X_{ns^1} \text{ (General Configuration for Group 1 and Hydrogen)}

💡Examples

Problem 1:

Explain why hydrogen acts as a reducing agent in its reaction with copper(II) oxide.

Solution:

CuO+H2Cu+H2OCuO + H_2 \rightarrow Cu + H_2O

Explanation:

In this reaction, Hydrogen removes oxygen from CuOCuO (reduction of copper) and itself gets oxidized to H2OH_2O. This behavior is similar to alkali metals which are strong reducing agents.

Problem 2:

Compare the oxidation states of Hydrogen in HClHCl and NaHNaH.

Solution:

In HClHCl, Hydrogen is in the +1+1 oxidation state. In NaHNaH, Hydrogen is in the 1-1 oxidation state.

Explanation:

In HClHCl, Hydrogen behaves like an alkali metal (electropositive). In NaHNaH (Sodium Hydride), it behaves like a halogen (electronegative) by accepting an electron from the metal.

Problem 3:

Calculate the number of protons and electrons in H+H^+.

Solution:

Protons = 11, Electrons = 00.

Explanation:

A neutral Hydrogen atom has 11 proton and 11 electron. When it loses its only electron to form the H+H^+ ion, only the nucleus (a single proton) remains.

Position of Hydrogen in Periodic Table Revision - Class 11 Chemistry ICSE