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Hydrogen - Heavy Water

Grade 11ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Heavy water is the oxide of deuterium (12H^2_1H or DD), represented by the formula D2OD_2O. It was discovered by Harold Urey in 1932.

Preparation: It is primarily prepared by the prolonged electrolysis of ordinary water (H2OH_2O) containing a small amount of alkali like NaOHNaOH.

Physical Properties: D2OD_2O is a colorless, odorless, and tasteless liquid. Its physical constants (Boiling Point: 374.42 K374.42 \text{ K}, Freezing Point: 281.0 K281.0 \text{ K}, Density: 1.106 g/cm31.106 \text{ g/cm}^3) are higher than those of ordinary water due to the higher molecular mass of deuterium.

Kinetic Isotope Effect: Chemical reactions of D2OD_2O are slower than those of H2OH_2O because the DOD-O bond is stronger than the HOH-O bond, requiring higher activation energy.

Biological Properties: Heavy water is injurious to humans, animals, and plants. it retards the growth of tobacco seeds and inhibits the development of tadpoles.

Nuclear Moderator: D2OD_2O is extensively used in nuclear reactors to slow down fast-moving neutrons to thermal speeds, facilitating a controlled nuclear chain reaction.

Exchange Reactions: When compounds containing reactive hydrogen are treated with D2OD_2O, hydrogen atoms are replaced by deuterium, e.g., NaOH+D2ONaOD+HDONaOH + D_2O \rightarrow NaOD + HDO.

📐Formulae

D2OD_2O

2D2OElectrolysis2D2+O22D_2O \xrightarrow{\text{Electrolysis}} 2D_2 + O_2

CaC2+2D2OCa(OD)2+C2D2 (Deuteroacetylene)CaC_2 + 2D_2O \rightarrow Ca(OD)_2 + C_2D_2 \text{ (Deuteroacetylene)}

Mg3N2+6D2O3Mg(OD)2+2ND3 (Deuteroammonia)Mg_3N_2 + 6D_2O \rightarrow 3Mg(OD)_2 + 2ND_3 \text{ (Deuteroammonia)}

P2O5+3D2O2D3PO4 (Deuterophosphoric acid)P_2O_5 + 3D_2O \rightarrow 2D_3PO_4 \text{ (Deuterophosphoric acid)}

Al4C3+12D2O4Al(OD)3+3CD4 (Deuteromethane)Al_4C_3 + 12D_2O \rightarrow 4Al(OD)_3 + 3CD_4 \text{ (Deuteromethane)}

SO3+D2OD2SO4 (Deuterosulphuric acid)SO_3 + D_2O \rightarrow D_2SO_4 \text{ (Deuterosulphuric acid)}

💡Examples

Problem 1:

Explain why the boiling point of D2OD_2O (101.42C101.42 ^\circ C) is higher than that of H2OH_2O (100C100 ^\circ C).

Solution:

The boiling point is higher because D2OD_2O has a higher molecular mass (20 u20 \text{ u}) compared to H2OH_2O (18 u18 \text{ u}).

Explanation:

Higher molecular mass results in stronger van der Waals forces and slightly stronger hydrogen bonding in heavy water, requiring more thermal energy to break the intermolecular forces during boiling.

Problem 2:

Write the chemical equation for the reaction of heavy water with Aluminum Carbide (Al4C3Al_4C_3).

Solution:

Al4C3+12D2O4Al(OD)3+3CD4Al_4C_3 + 12D_2O \rightarrow 4Al(OD)_3 + 3CD_4

Explanation:

This is a hydrolysis-like reaction where heavy water reacts with a metal carbide to produce a metal deuteroxide and a deutero-hydrocarbon (in this case, deuteromethane).

Problem 3:

What happens when Heavy Water is added to Calcium Oxide (CaOCaO)?

Solution:

CaO+D2OCa(OD)2CaO + D_2O \rightarrow Ca(OD)_2

Explanation:

Similar to the reaction of H2OH_2O with quicklime, D2OD_2O reacts with basic oxides to form the corresponding deuteroxide (Calcium deuteroxide).

Heavy Water - Revision Notes & Key Formulas | ICSE Class 11 Chemistry