Review the key concepts, formulae, and examples before starting your quiz.
πConcepts
Alkanes are saturated open-chain hydrocarbons containing carbon-carbon single bonds with the general formula .
In alkanes, every carbon atom is hybridized, forming four sigma bonds in a tetrahedral geometry with a bond angle of .
Preparation via Sabatier-Senderens Reaction: Hydrogenation of alkenes or alkynes using catalysts like , , or at specific temperatures.
Wurtz Reaction: Treatment of alkyl halides with sodium metal in dry ether to produce higher alkanes with an even number of carbon atoms ().
Decarboxylation: Heating sodium salts of carboxylic acids with soda lime ( and in ratio) to yield an alkane with one less carbon atom than the parent salt.
Kolbe's Electrolytic Method: Electrolysis of an aqueous solution of sodium or potassium salt of a carboxylic acid gives alkanes at the anode.
Substitution Reactions: Alkanes undergo free radical substitution, most notably halogenation in the presence of light or heat ().
Combustion: Alkanes burn in oxygen to produce , , and a large amount of heat ( is negative).
Isomerization: -Alkanes heated with anhydrous and gas rearrange to form branched-chain isomers.
Aromatization: Alkanes with six or more carbon atoms heated to at atm over oxides of , , or get dehydrogenated and cyclized to benzene or its derivatives.
πFormulae
π‘Examples
Problem 1:
Explain why the Wurtz reaction is not preferred for the preparation of unsymmetrical alkanes like propane ().
Solution:
If a mixture of two different alkyl halides (e.g., and ) is used, three different alkanes are formed: ethane (), propane (), and butane ().
Explanation:
The mixture of these alkanes has very close boiling points, making it extremely difficult to separate the desired unsymmetrical alkane (propane) in pure form, resulting in a low yield.
Problem 2:
Write the chemical equation for the preparation of ethane from sodium propionate using the decarboxylation method.
Solution:
Explanation:
Sodium propionate reacts with soda lime. The carboxyl group is removed as , leaving behind the ethyl group which combines with hydrogen to form ethane ().
Problem 3:
Identify the major product when -hexane is heated with anhydrous and .
Solution:
The major products are branched-chain isomers: -methylpentane and -methylpentane.
Explanation:
This is an isomerization reaction where straight-chain alkanes convert into branched-chain isomers in the presence of catalyst.