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Classification of Elements and Periodicity - Periodic Trends in Physical Properties

Grade 11ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Atomic Radius: It is the distance from the center of the nucleus to the outermost shell containing electrons. Across a period, atomic radius decreases because the effective nuclear charge (ZeffZ_{eff}) increases. Down a group, it increases due to the addition of a new energy shell.

Ionic Radius: The distance between the nucleus and the electron in the outermost shell of an ion. Cations are smaller than their parent atoms (rcation<ratomr_{cation} < r_{atom}), while anions are larger (ranion>ratomr_{anion} > r_{atom}).

Ionization Enthalpy (ΔiH\Delta_i H): The minimum energy required to remove the most loosely bound electron from an isolated gaseous atom in its ground state. It increases across a period and decreases down a group.

Electron Gain Enthalpy (ΔegH\Delta_{eg} H): The enthalpy change when an electron is added to an isolated gaseous atom to form a negative ion. Halogens have highly negative ΔegH\Delta_{eg} H because they achieve a stable noble gas configuration.

Electronegativity (χ\chi): A qualitative measure of the ability of an atom in a chemical compound to attract shared electrons to itself. Fluorine is the most electronegative element with a value of 4.04.0 on the Pauling scale.

Screening Effect (Shielding Effect): The reduction in the nuclear pull on valence electrons due to the presence of inner shell electrons. Effective nuclear charge is given by Zeff=ZσZ_{eff} = Z - \sigma, where σ\sigma is the shielding constant.

Periodic Trends in Chemical Reactivity: Reactivity is high at the extremes of a period (alkali metals and halogens) and lowest in the center and for noble gases. Metallic character decreases across a period and increases down a group.

📐Formulae

Zeff=ZσZ_{eff} = Z - \sigma

ΔiH=EEground\Delta_i H = E_{\infty} - E_{ground}

χP=0.336(χM0.615)\chi_P = 0.336 (\chi_M - 0.615) (Relation between Pauling and Mulliken scale)

Electronegativity (Mulliken)=I.E.+E.A.2\text{Electronegativity (Mulliken)} = \frac{I.E. + E.A.}{2}

rcovalent=12×(Inter-nuclear distance between two bonded atoms)r_{covalent} = \frac{1}{2} \times (\text{Inter-nuclear distance between two bonded atoms})

💡Examples

Problem 1:

Arrange the following isoelectronic species in increasing order of their ionic radii: N3N^{3-}, O2O^{2-}, FF^-, Na+Na^+, Mg2+Mg^{2+}, Al3+Al^{3+}.

Solution:

Al3+<Mg2+<Na+<F<O2<N3Al^{3+} < Mg^{2+} < Na^+ < F^- < O^{2-} < N^{3-}

Explanation:

For isoelectronic species (ions with the same number of electrons), the ionic radius decreases as the nuclear charge (ZZ) increases. Al3+Al^{3+} has Z=13Z=13 while N3N^{3-} has Z=7Z=7; hence, the nucleus of Al3+Al^{3+} exerts a stronger pull on the same number of electrons (10e10 e^-).

Problem 2:

Why is the first ionization enthalpy of Nitrogen (NN) higher than that of Oxygen (OO)?

Solution:

ΔiH1(N)>ΔiH1(O)\Delta_i H_1 (N) > \Delta_i H_1 (O)

Explanation:

The electronic configuration of Nitrogen is 1s22s22p31s^2 2s^2 2p^3, which has a half-filled pp-subshell. Half-filled and completely filled configurations are extra stable due to symmetry and exchange energy. Oxygen (1s22s22p41s^2 2s^2 2p^4) does not have this stability, making it easier to remove one electron to reach a stable half-filled state.

Problem 3:

Between ClCl and FF, which element has a more negative electron gain enthalpy (ΔegH\Delta_{eg} H)?

Solution:

ClCl has a more negative ΔegH\Delta_{eg} H than FF.

Explanation:

Although FF is more electronegative, it is a very small atom. Adding an electron to the compact 2p2p subshell of FF leads to significant inter-electronic repulsion. In ClCl, the electron enters the larger 3p3p subshell, where electron-electron repulsion is much less, resulting in a more exothermic process.

Periodic Trends in Physical Properties Revision - Class 11 Chemistry ICSE