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Classification of Elements and Periodicity - Modern Periodic Law

Grade 11ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Modern Periodic Law states that the physical and chemical properties of the elements are periodic functions of their atomic numbers (ZZ). This shifted the basis of classification from atomic mass (AA) to atomic number.

Henry Moseley demonstrated that the atomic number is a more fundamental property than atomic mass by plotting ν\sqrt{\nu} (square root of X-ray frequency) against ZZ, resulting in a straight line.

The Long Form of the Periodic Table is divided into four main blocks based on the orbital being filled: ss-block, pp-block, dd-block, and ff-block.

The ss-block elements (Groups 11 and 22) and pp-block elements (Groups 1313 to 1818) are collectively known as Representative Elements or Main Group Elements.

The dd-block elements (Groups 33 to 1212) are known as Transition Elements because they represent a transition in properties between the highly electropositive ss-block and highly electronegative pp-block.

The ff-block elements (Lanthanoids and Actinoids) are known as Inner Transition Elements and are placed separately at the bottom of the table.

Periodicity refers to the recurrence of similar properties after regular intervals. This is due to the recurrence of similar outer electronic configurations.

📐Formulae

ν=a(Zb)\sqrt{\nu} = a(Z - b) (where ν\nu is the frequency of X-rays, ZZ is the atomic number, and a,ba, b are constants)

Zeff=ZσZ_{eff} = Z - \sigma (Effective Nuclear Charge, where σ\sigma is the screening or shielding constant)

ns12ns^{1-2} (General configuration of ss-block elements)

ns2np16ns^2 np^{1-6} (General configuration of pp-block elements)

(n1)d110ns12(n-1)d^{1-10} ns^{1-2} (General configuration of dd-block elements)

(n2)f114(n1)d01ns2(n-2)f^{1-14} (n-1)d^{0-1} ns^2 (General configuration of ff-block elements)

💡Examples

Problem 1:

Determine the position (period and group) of an element with atomic number Z=24Z = 24 in the Modern Periodic Table.

Solution:

The electronic configuration of Z=24Z = 24 (Chromium) is [Ar]3d54s1[Ar] 3d^5 4s^1. Period: 44 (since the highest principal quantum number nn is 44). Group: 66 (calculated as sum of (n1)d(n-1)d and nsns electrons: 5+1=65 + 1 = 6). Block: dd-block.

Explanation:

In the Modern Periodic Table, the period is determined by the highest energy level (nn) being filled. For dd-block elements, the group number is the sum of electrons in the (n1)d(n-1)d and nsns subshells.

Problem 2:

Identify which of the following has the largest atomic radius: MgMg (Z=12Z=12), PP (Z=15Z=15), or ClCl (Z=17Z=17).

Solution:

MgMg has the largest atomic radius.

Explanation:

All three elements belong to the 3rd3^{rd} period. Across a period from left to right, the atomic number and effective nuclear charge (ZeffZ_{eff}) increase while the number of shells remains constant. This results in a stronger pull on the electrons towards the nucleus, causing the atomic radius to decrease. Thus, MgMg (the leftmost element) is the largest.

Modern Periodic Law - Revision Notes & Key Formulas | ICSE Class 11 Chemistry