Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Effective Nuclear Charge (): The net positive charge experienced by valence electrons. It is calculated as , where is the atomic number and is the number of shielding electrons. increases across a period but remains relatively constant down a group.
Atomic Radius: The distance from the nucleus to the outermost electron shell. It decreases across a period due to increasing pulling electrons closer, and increases down a group due to the addition of new principal energy levels ().
Ionic Radius: Cations (e.g., ) are smaller than their parent atoms because they lose an electron shell and have increased . Anions (e.g., ) are larger than their parent atoms due to increased inter-electron repulsion in the valence shell.
First Ionization Energy (): The energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous ions. Trend: Increases across a period, decreases down a group.
Electronegativity: A relative measure of the attraction an atom has for a shared pair of electrons in a covalent bond. Trends follow the pattern, peaking at Fluorine ().
Electron Affinity (): The energy change when one mole of electrons is added to one mole of gaseous atoms. Values generally become more exothermic (more negative) across a period.
Melting Points: Depend on the type of bonding. In Period 3, melting points increase from to (metallic bonding strength), peak at (giant covalent structure), and then drop for , , (weak London dispersion forces).
Oxide Periodicity: Period 3 oxides transition from basic (, ) to amphoteric () to acidic (, , , ).
📐Formulae
(Basic Oxide)
(Acidic Oxide)
(Amphoteric Behavior)
💡Examples
Problem 1:
Explain why the first ionization energy of Aluminum () is lower than that of Magnesium ().
Solution:
vs.
Explanation:
The electron removed from is in the subshell, which is at a higher energy level and further from the nucleus than the subshell of . Additionally, the electron is slightly shielded by the electrons, making it easier to remove despite the higher nuclear charge of .
Problem 2:
Compare the atomic radius of and and justify the difference.
Solution:
Explanation:
Both elements are in Period 3 and have electrons in the same principal energy level (). However, has more protons () than (). This results in a higher effective nuclear charge () in , which pulls the outer electrons more strongly toward the nucleus, resulting in a smaller atomic radius.
Problem 3:
Identify the nature of the oxide formed by Sulfur and write its reaction with water.
Solution:
Explanation:
Sulfur is a non-metal. Non-metal oxides are generally acidic. reacts with water to form sulfuric acid (), which is a strong acid.