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Organic Chemistry - Fundamentals of organic chemistry

Grade 11IBChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A homologous series is a series of compounds with the same functional group and general formula. Members show a gradation in physical properties, such as boiling point, which increases with the number of carbon atoms due to increased London dispersion forces.

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Functional groups are specific atoms or groups of atoms within a molecule that determine its chemical reactivity. Examples include the hydroxyl group (−OH-OH) in alcohols and the carboxyl group (−COOH-COOH) in carboxylic acids.

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Structural isomers are compounds that have the same molecular formula but different structural arrangements of atoms (e.g., CH3CH2CH2CH3CH_3CH_2CH_2CH_3 and CH3CH(CH3)CH3CH_3CH(CH_3)CH_3).

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Saturated hydrocarbons (alkanes) contain only single C−CC-C bonds, while unsaturated hydrocarbons (alkenes, alkynes) contain double (C=CC=C) or triple (C≡CC\equiv C) carbon-carbon bonds.

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Benzene (C6H6C_6H_6) is an aromatic hydrocarbon. It exists as a planar hexagonal ring with delocalized π\pi electrons, which provides extra stability compared to theoretical cyclic alkenes.

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Carbon atoms are classified as primary (1∘1^\circ), secondary (2∘2^\circ), or tertiary (3∘3^\circ) based on how many other carbon atoms are bonded to the carbon atom attached to the functional group.

📐Formulae

CnH2n+2 (General formula for Alkanes)C_nH_{2n+2} \text{ (General formula for Alkanes)}

CnH2n (General formula for Alkenes)C_nH_{2n} \text{ (General formula for Alkenes)}

CnH2n−2 (General formula for Alkynes)C_nH_{2n-2} \text{ (General formula for Alkynes)}

CnH2n+1OH (General formula for Alcohols)C_nH_{2n+1}OH \text{ (General formula for Alcohols)}

CnH2n+1COOH (General formula for Carboxylic Acids)C_nH_{2n+1}COOH \text{ (General formula for Carboxylic Acids)}

CnH2n+1X (General formula for Halogenoalkanes, where X=F,Cl,Br,I)C_nH_{2n+1}X \text{ (General formula for Halogenoalkanes, where } X = F, Cl, Br, I)

💡Examples

Problem 1:

Provide the IUPAC name for the molecule: CH3CH(CH3)CH2CH2CHOCH_3CH(CH_3)CH_2CH_2CHO.

Solution:

44-methylpentanal

Explanation:

The longest carbon chain containing the aldehyde functional group (−CHO-CHO) has 55 carbons (pentanal). Numbering begins at the carbonyl carbon. A methyl substituent is located on the 4th4^{th} carbon.

Problem 2:

Identify the number of structural isomers for the alkane C4H10C_4H_{10}.

Solution:

22 isomers

Explanation:

The two isomers are butane (CH3CH2CH2CH3CH_3CH_2CH_2CH_3) and 22-methylpropane (CH3CH(CH3)CH3CH_3CH(CH_3)CH_3).

Problem 3:

Classify CH3C(CH3)2OHCH_3C(CH_3)_2OH as a primary, secondary, or tertiary alcohol.

Solution:

Tertiary (3∘3^\circ) alcohol

Explanation:

The carbon atom bonded to the hydroxyl (−OH-OH) group is bonded to three other carbon atoms (methyl groups), making it a tertiary carbon.