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Organic Chemistry - Fundamentals of organic chemistry

Grade 11IBChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A homologous series is a series of compounds with the same functional group and general formula. Members show a gradation in physical properties, such as boiling point, which increases with the number of carbon atoms due to increased London dispersion forces.

Functional groups are specific atoms or groups of atoms within a molecule that determine its chemical reactivity. Examples include the hydroxyl group (OH-OH) in alcohols and the carboxyl group (COOH-COOH) in carboxylic acids.

Structural isomers are compounds that have the same molecular formula but different structural arrangements of atoms (e.g., CH3CH2CH2CH3CH_3CH_2CH_2CH_3 and CH3CH(CH3)CH3CH_3CH(CH_3)CH_3).

Saturated hydrocarbons (alkanes) contain only single CCC-C bonds, while unsaturated hydrocarbons (alkenes, alkynes) contain double (C=CC=C) or triple (CCC\equiv C) carbon-carbon bonds.

Benzene (C6H6C_6H_6) is an aromatic hydrocarbon. It exists as a planar hexagonal ring with delocalized π\pi electrons, which provides extra stability compared to theoretical cyclic alkenes.

Carbon atoms are classified as primary (11^\circ), secondary (22^\circ), or tertiary (33^\circ) based on how many other carbon atoms are bonded to the carbon atom attached to the functional group.

📐Formulae

CnH2n+2 (General formula for Alkanes)C_nH_{2n+2} \text{ (General formula for Alkanes)}

CnH2n (General formula for Alkenes)C_nH_{2n} \text{ (General formula for Alkenes)}

CnH2n2 (General formula for Alkynes)C_nH_{2n-2} \text{ (General formula for Alkynes)}

CnH2n+1OH (General formula for Alcohols)C_nH_{2n+1}OH \text{ (General formula for Alcohols)}

CnH2n+1COOH (General formula for Carboxylic Acids)C_nH_{2n+1}COOH \text{ (General formula for Carboxylic Acids)}

CnH2n+1X (General formula for Halogenoalkanes, where X=F,Cl,Br,I)C_nH_{2n+1}X \text{ (General formula for Halogenoalkanes, where } X = F, Cl, Br, I)

💡Examples

Problem 1:

Provide the IUPAC name for the molecule: CH3CH(CH3)CH2CH2CHOCH_3CH(CH_3)CH_2CH_2CHO.

Solution:

44-methylpentanal

Explanation:

The longest carbon chain containing the aldehyde functional group (CHO-CHO) has 55 carbons (pentanal). Numbering begins at the carbonyl carbon. A methyl substituent is located on the 4th4^{th} carbon.

Problem 2:

Identify the number of structural isomers for the alkane C4H10C_4H_{10}.

Solution:

22 isomers

Explanation:

The two isomers are butane (CH3CH2CH2CH3CH_3CH_2CH_2CH_3) and 22-methylpropane (CH3CH(CH3)CH3CH_3CH(CH_3)CH_3).

Problem 3:

Classify CH3C(CH3)2OHCH_3C(CH_3)_2OH as a primary, secondary, or tertiary alcohol.

Solution:

Tertiary (33^\circ) alcohol

Explanation:

The carbon atom bonded to the hydroxyl (OH-OH) group is bonded to three other carbon atoms (methyl groups), making it a tertiary carbon.

Fundamentals of organic chemistry - Revision Notes & Key Formulas | IB Grade 11 Chemistry