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Organic Chemistry - Functional group chemistry

Grade 11IBChemistry

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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A homologous series is a series of compounds that can be described by a general formula, such as CnH2n+2C_nH_{2n+2} for alkanes. Members show a gradation in physical properties and similar chemical properties.

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Functional groups are specific atoms or groups of atoms within a molecule that determine its chemical reactivity. Examples include the hydroxyl group (βˆ’OH-OH) in alcohols and the carboxyl group (βˆ’COOH-COOH) in carboxylic acids.

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Saturated compounds contain only single carbon-carbon bonds (e.g., CH3CH3CH_3CH_3), while unsaturated compounds contain at least one double or triple carbon-carbon bond (e.g., CH2=CH2CH_2=CH_2).

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IUPAC nomenclature provides a systematic way to name organic compounds based on the longest carbon chain (stem), the primary functional group (suffix), and any side chains or substituents (prefix).

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Structural isomers are molecules that share the same molecular formula but have different structural formulas, such as CH3CH2CH2OHCH_3CH_2CH_2OH (propan-1-ol) and CH3CH(OH)CH3CH_3CH(OH)CH_3 (propan-2-ol).

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Primary (1∘1^{\circ}), secondary (2∘2^{\circ}), and tertiary (3∘3^{\circ}) classifications describe the carbon atom attached to the functional group based on how many other carbon atoms are bonded to it.

πŸ“Formulae

CnH2n+2Β (Alkanes)C_nH_{2n+2} \text{ (Alkanes)}

CnH2nΒ (Alkenes)C_nH_{2n} \text{ (Alkenes)}

CnH2nβˆ’2Β (Alkynes)C_nH_{2n-2} \text{ (Alkynes)}

CnH2n+1OHΒ (Alcohols)C_nH_{2n+1}OH \text{ (Alcohols)}

CnH2n+1CHOΒ (Aldehydes)C_nH_{2n+1}CHO \text{ (Aldehydes)}

CnH2n+1COOHΒ (CarboxylicΒ Acids)C_nH_{2n+1}COOH \text{ (Carboxylic Acids)}

πŸ’‘Examples

Problem 1:

Identify the IUPAC name and functional group for the molecule CH3COCH2CH3CH_3COCH_2CH_3.

Solution:

The IUPAC name is butan-2-one. The functional group is a ketone (carbonyl group).

Explanation:

The molecule has a four-carbon chain (but-), contains only single C-C bonds in the skeleton (-an-), and has a double-bonded oxygen on the second carbon, which is the ketone functional group (-one).

Problem 2:

Determine the molecular formula and draw the structural isomers for an alkane with n=4n=4.

Solution:

Molecular formula: C4H10C_4H_{10}. Isomers: Butane (CH3CH2CH2CH3CH_3CH_2CH_2CH_3) and 2-methylpropane (CH(CH3)3CH(CH_3)_3).

Explanation:

Using the general formula CnH2n+2C_nH_{2n+2}, for n=4n=4, we get C4H4(2)+2=C4H10C_4H_{4(2)+2} = C_4H_{10}. There are two ways to arrange four carbons in a saturated chain: a straight chain or a branched chain.

Problem 3:

Classify the alcohol CH3C(CH3)2OHCH_3C(CH_3)_2OH as primary, secondary, or tertiary.

Solution:

Tertiary (3∘3^{\circ}) alcohol.

Explanation:

The carbon atom bonded to the hydroxyl group (βˆ’OH-OH) is bonded to three other carbon atoms (CH3CH_3 groups), making it a tertiary carbon.

Functional group chemistry - Revision Notes & Key Formulas | IB Grade 11 Chemistry