Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Oxidation Number (O.N.) is defined as the formal charge that an atom would carry in a molecule or ion if the shared electrons in a covalent bond were assigned completely to the more electronegative element.
Rules for assigning O.N.: (1) In free or elementary state (e.g., , , , , ), the O.N. of each atom is . (2) For monatomic ions, the O.N. is equal to the charge of the ion (e.g., is , is , is ).
Oxygen Rule: In most compounds, the O.N. of oxygen is . Exceptions include peroxides (e.g., , ) where it is , superoxides (e.g., ) where it is , and in where it is .
Hydrogen Rule: The O.N. of hydrogen is when bonded to non-metals. However, in metal hydrides (e.g., , ), it is .
Halogen Rule: Fluorine, being the most electronegative element, always has an O.N. of . Other halogens (, , ) are typically unless combined with oxygen or fluorine.
In a neutral molecule, the algebraic sum of the oxidation numbers of all constituent atoms must be . In a polyatomic ion, the sum must equal the net charge of the ion.
Oxidation is defined as an increase in the oxidation number of an element, whereas Reduction is defined as a decrease in the oxidation number of an element.
Stock Notation: The oxidation state of a metal in a compound is represented by a Roman numeral in parentheses after the symbol of the metal (e.g., is Iron(II) oxide, is Iron(III) oxide).
📐Formulae
💡Examples
Problem 1:
Calculate the oxidation number of in .
Solution:
Explanation:
The O.N. of is and is . Let the O.N. of be . Since the molecule is neutral, the sum of oxidation numbers is zero.
Problem 2:
Calculate the oxidation number of in .
Solution:
Explanation:
Let the O.N. of be . The sum of oxidation numbers must equal the charge of the ion, which is .
Problem 3:
Identify the oxidant and reductant in the reaction: .
Solution:
Reductant: , Oxidant:
Explanation:
The O.N. of increases from to (Oxidation), so is the reducing agent (reductant). The O.N. of decreases from to (Reduction), so is the oxidizing agent (oxidant).
Problem 4:
Calculate the oxidation number of in .
Solution:
Explanation:
Potassium () is an alkali metal with O.N. , and Oxygen () is . The sum of the oxidation numbers in the neutral compound is .