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Equilibrium - Equilibrium in Physical Processes

Grade 11CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Equilibrium in physical processes refers to a state where two different phases of a substance coexist, and the rate of transfer of molecules from one phase to another is equal to the rate of the reverse process.

Dynamic Nature: Physical equilibrium is dynamic, meaning the forward and backward processes continue to occur at the same rate even though no macroscopic change is visible.

Solid-Liquid Equilibrium: This occurs at the melting point. For a pure substance at 1 atm1 \text{ atm}, the temperature is the normal melting point. Example: H2O(s)H2O(l)H_2O(s) \rightleftharpoons H_2O(l) at 273 K273 \text{ K}.

Liquid-Vapor Equilibrium: In a closed container, the pressure exerted by vapors in equilibrium with the liquid at a constant temperature is the equilibrium vapor pressure. Example: H2O(l)H2O(g)H_2O(l) \rightleftharpoons H_2O(g).

Solid-Vapor Equilibrium: This involves sublimation, where a solid directly converts to vapor. Example: I2(s)I2(g)I_2(s) \rightleftharpoons I_2(g). The intensity of color (for iodine) remains constant once equilibrium is reached.

Equilibrium involving Dissolution of Solids in Liquids: A saturated solution represents an equilibrium between the undissolved solute and the solute in the solution: Sugar(s)Sugar(aq)Sugar(s) \rightleftharpoons Sugar(aq).

Equilibrium involving Dissolution of Gases in Liquids: Governed by Henry's Law, which states that the solubility of a gas in a liquid at a given temperature is directly proportional to the pressure of the gas above the liquid.

General Characteristics: Equilibrium is possible only in a closed system at constant temperature. Measurable properties like pressure, concentration, and density remain constant at equilibrium.

📐Formulae

Rate of Melting=Rate of Freezing\text{Rate of Melting} = \text{Rate of Freezing}

Rate of Evaporation=Rate of Condensation\text{Rate of Evaporation} = \text{Rate of Condensation}

p=KHxp = K_H \cdot x

m=kpm = k \cdot p

SolubilityPressure (at constant temperature)\text{Solubility} \propto \text{Pressure (at constant temperature)}

💡Examples

Problem 1:

A closed vessel contains water and water vapor in equilibrium at 373 K373 \text{ K} and 1.013 bar1.013 \text{ bar} pressure. If the volume of the container is suddenly increased at constant temperature, what will be the effect on the vapor pressure once a new equilibrium is established?

Solution:

The vapor pressure will remain the same (1.013 bar1.013 \text{ bar}) provided some liquid water is still present.

Explanation:

At a constant temperature, the equilibrium vapor pressure of a liquid is a characteristic property and does not depend on the volume of the container or the amount of liquid/vapor present, as long as both phases coexist.

Problem 2:

Explain the observation when a bottle of soda water is opened.

Solution:

When the bottle is opened, the pressure above the liquid decreases, causing CO2CO_2 gas to fizz out of the solution.

Explanation:

According to Henry's Law (p=KHxp = K_H \cdot x), the solubility of a gas is proportional to its partial pressure. Decreasing the pressure (pp) decreases the mole fraction (xx) of CO2CO_2 dissolved in the liquid, shifting the equilibrium CO2(g)CO2(aq)CO_2(g) \rightleftharpoons CO_2(aq) to the left.

Equilibrium in Physical Processes Revision - Class 11 Chemistry CBSE