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Equilibrium - Equilibrium in Chemical Processes (Dynamic Equilibrium)

Grade 11CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Chemical equilibrium is a state in a reversible reaction where the rate of the forward reaction equals the rate of the backward reaction, denoted as rf=rbr_f = r_b.

Equilibrium is dynamic in nature, meaning the forward and reverse reactions continue to occur at the molecular level, but the macroscopic properties (concentration, pressure, color) remain constant over time.

For a general reaction aA+bBcC+dDaA + bB \rightleftharpoons cC + dD, the Law of Mass Action states that the equilibrium constant KcK_c is the ratio of the product of molar concentrations of products to that of reactants, each raised to the power of their stoichiometric coefficients.

In homogeneous equilibrium, all reactants and products are in the same phase (e.g., all gases or all in aqueous solution).

In heterogeneous equilibrium, substances are in different phases. The concentrations of pure solids and pure liquids are taken as unity (11) and are omitted from the KcK_c and KpK_p expressions.

The equilibrium constant KK is temperature-dependent. It does not change with changes in concentration, pressure, or the addition of a catalyst.

📐Formulae

Kc=[C]c[D]d[A]a[B]bK_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}

Kp=(PC)c(PD)d(PA)a(PB)bK_p = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b}

Kp=Kc(RT)ΔngK_p = K_c(RT)^{\Delta n_g}

Δng=nproducts(g)nreactants(g)\Delta n_g = \sum n_{products(g)} - \sum n_{reactants(g)}

Qc=[C]tc[D]td[A]ta[B]tb (Reaction Quotient at any time t)Q_c = \frac{[C]_t^c [D]_t^d}{[A]_t^a [B]_t^b} \text{ (Reaction Quotient at any time } t)

💡Examples

Problem 1:

For the Haber process reaction: N2(g)+3H2(g)2NH3(g)N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g), calculate Δng\Delta n_g and state the relationship between KpK_p and KcK_c.

Solution:

  1. Identify the number of gaseous moles of products: np=2n_p = 2 (for NH3NH_3).
  2. Identify the number of gaseous moles of reactants: nr=1+3=4n_r = 1 + 3 = 4 (for N2N_2 and H2H_2).
  3. Calculate Δng=npnr=24=2\Delta n_g = n_p - n_r = 2 - 4 = -2.
  4. Relationship: Kp=Kc(RT)2K_p = K_c(RT)^{-2} or Kp=Kc(RT)2K_p = \frac{K_c}{(RT)^2}.

Explanation:

The value of Δng\Delta n_g is derived only from gaseous components. Since Δng\Delta n_g is negative, Kc>KpK_c > K_p for this specific reaction.

Problem 2:

Calculate KcK_c for the reaction H2(g)+I2(g)2HI(g)H_2(g) + I_2(g) \rightleftharpoons 2HI(g) if at equilibrium [H2]=0.5 mol L1[H_2] = 0.5 \text{ mol L}^{-1}, [I2]=0.5 mol L1[I_2] = 0.5 \text{ mol L}^{-1}, and [HI]=1.0 mol L1[HI] = 1.0 \text{ mol L}^{-1}.

Solution:

Using the formula for KcK_c: Kc=[HI]2[H2][I2]K_c = \frac{[HI]^2}{[H_2][I_2]} Kc=(1.0)2(0.5)(0.5)K_c = \frac{(1.0)^2}{(0.5)(0.5)} Kc=1.00.25=4K_c = \frac{1.0}{0.25} = 4

Explanation:

The equilibrium constant is calculated by substituting the equilibrium molar concentrations into the expression derived from the stoichiometric equation.

Equilibrium in Chemical Processes (Dynamic Equilibrium) Revision - Class 11 Chemistry CBSE