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Classification of Elements and Periodicity in Properties - Periodic Trends in Properties of Elements

Grade 11CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Periodic Trends in Atomic Radius: Across a period, the atomic radius decreases due to an increase in the effective nuclear charge (ZeffZ_{eff}) which pulls the electrons closer. Down a group, the atomic radius increases because new principal energy shells (nn) are added.

Ionic Radius: Cations are smaller than their parent atoms (e.g., Na+<NaNa^+ < Na) due to increased ZeffZ_{eff}. Anions are larger than their parent atoms (e.g., Cl>ClCl^- > Cl) because of increased inter-electronic repulsion and decreased ZeffZ_{eff} per electron.

Isoelectronic Species: For atoms/ions with the same number of electrons, the radius decreases as the atomic number (ZZ) increases. Example: O2>F>Na+>Mg2+O^{2-} > F^- > Na^+ > Mg^{2+}.

Ionization Enthalpy (ΔiH{\Delta}_i H): It is the energy required to remove an electron from an isolated gaseous atom. It increases across a period (increasing ZeffZ_{eff}) and decreases down a group (increasing atomic size and shielding effect).

Electron Gain Enthalpy (ΔegH{\Delta}_{eg} H): The enthalpy change when an electron is added to a neutral gaseous atom. Halogens have highly negative ΔegH{\Delta}_{eg} H. ClCl has a more negative ΔegH{\Delta}_{eg} H than FF due to less inter-electronic repulsion in ClCl's larger 3p3p orbital.

Electronegativity: The ability of an atom in a chemical compound to attract shared electrons. According to the Pauling scale, Fluorine (FF) is the most electronegative (4.04.0) and Cesium (CsCs) is the least.

Valency and Oxidation States: Valency across a period increases from 11 to 44 and then decreases to 00 for noble gases. Elements in the same group usually exhibit the same valence.

Anomalous Properties of Second Period Elements: The first element of each group (Li,Be,B,C,N,O,FLi, Be, B, C, N, O, F) shows different behavior due to small size, high electronegativity, high ionization enthalpy, and absence of vacant dd-orbitals.

📐Formulae

Zeff=ZσZ_{eff} = Z - \sigma

XAXB=0.102Δ where Δ=EABEAA×EBBX_A - X_B = 0.102 \sqrt{\Delta} \text{ where } \Delta = E_{A-B} - \sqrt{E_{A-A} \times E_{B-B}}

Metallic Character1Ionization Enthalpy\text{Metallic Character} \propto \frac{1}{\text{Ionization Enthalpy}}

Atomic Radius (Covalent)=dAA2\text{Atomic Radius (Covalent)} = \frac{d_{A-A}}{2}

💡Examples

Problem 1:

Which of the following has the highest negative electron gain enthalpy: FF, ClCl, BrBr, or II?

Solution:

ClCl (Chlorine)

Explanation:

Although FF is more electronegative, its small size leads to strong inter-electronic repulsions in the 2p2p subshell, making the addition of an electron less exothermic than in ClCl.

Problem 2:

Arrange the following in increasing order of first ionization enthalpy: B,C,N,OB, C, N, O.

Solution:

B<C<O<NB < C < O < N

Explanation:

NN has a higher ionization enthalpy than OO because NN has a stable half-filled electronic configuration (2s22p32s^2 2p^3), making it harder to remove an electron.

Problem 3:

Predict the formula of the stable binary compound formed by Magnesium (MgMg) and Nitrogen (NN).

Solution:

Mg3N2Mg_3N_2

Explanation:

Magnesium belongs to Group 2 (valency +2+2) and Nitrogen belongs to Group 15 (valency 3-3). Crossing the valencies gives Mg3N2Mg_3N_2.

Periodic Trends in Properties of Elements Revision - Class 11 Chemistry CBSE