krit.club logo

Classification of Elements and Periodicity in Properties - Electron Gain Enthalpy

Grade 11CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Electron Gain Enthalpy (DeltaegH\\Delta_{eg}H) is the enthalpy change that occurs when an electron is added to an isolated gaseous atom to form a negative ion: X(g)+eX(g)X(g) + e^- \rightarrow X^-(g).

Depending on the element, the process can be exothermic (negative DeltaegH\\Delta_{eg}H) or endothermic (positive DeltaegH\\Delta_{eg}H). Most elements release energy when they gain an electron.

Across a period (left to right), DeltaegH\\Delta_{eg}H generally becomes more negative because the atomic radius decreases and the effective nuclear charge (ZeffZ_{eff}) increases, leading to a stronger attraction for the incoming electron.

Down a group, DeltaegH\\Delta_{eg}H generally becomes less negative because the atomic size increases, and the incoming electron is farther from the nucleus, experiencing less attraction.

Group 17 (Halogens) have the most negative electron gain enthalpies because they only need one electron to achieve a stable noble gas configuration.

Noble gases (Group 18) have large positive electron gain enthalpies because the added electron has to enter a higher principal quantum level, creating a highly unstable configuration.

The DeltaegH\\Delta_{eg}H of ClCl is more negative than that of FF. This is because the 2p2p subshell in FF is very compact, leading to significant inter-electronic repulsion when an electron is added, whereas the 3p3p subshell in ClCl is larger and accommodates the electron more easily.

Successive electron gain enthalpies: Adding a second electron to a uninegative ion (e.g., O(g)+eO2(g)O^-(g) + e^- \rightarrow O^{2-}(g)) is always endothermic (DeltaegH>0\\Delta_{eg}H > 0) due to the strong electrostatic repulsion between the negative ion and the incoming electron.

📐Formulae

X(g)+eX(g)(ΔH=ΔegH1)X(g) + e^- \rightarrow X^-(g) \quad (\Delta H = \Delta_{eg}H_1)

X(g)+eX2(g)(ΔH=ΔegH2>0)X^-(g) + e^- \rightarrow X^{2-}(g) \quad (\Delta H = \Delta_{eg}H_2 > 0)

💡Examples

Problem 1:

Which of the following has the most negative electron gain enthalpy: FF, ClCl, BrBr, or II?

Solution:

ClCl (Chlorine)

Explanation:

While ΔegH\Delta_{eg}H generally becomes less negative down the group, ClCl is an exception. FF is very small, and the incoming electron faces high inter-electronic repulsion in the 2p2p shell. In ClCl, the 3p3p orbital is larger, reducing repulsion and making the addition of an electron more exothermic than in FF.

Problem 2:

Explain why the second electron gain enthalpy of Oxygen (O+eOO + e^- \rightarrow O^-; O+eO2O^- + e^- \rightarrow O^{2-}) is positive.

Solution:

ΔegH2>0\Delta_{eg}H_2 > 0

Explanation:

The first electron gain involves adding an electron to a neutral atom, which is exothermic. However, the second electron must be added to a negatively charged ion (OO^-). The strong electrostatic repulsion between the negative ion and the incoming electron requires energy to be supplied to overcome the force, making the process endothermic.

Problem 3:

Arrange the following in increasing order of negative electron gain enthalpy: OO, SS, FF, ClCl.

Solution:

O<S<F<ClO < S < F < Cl

Explanation:

Halogens have more negative ΔegH\Delta_{eg}H than chalcogens because they are closer to achieving a noble gas configuration. Between OO and SS, SS is more negative due to less electronic repulsion in the 3p3p shell. Similarly, ClCl is more negative than FF.