krit.club logo

Classification of Elements and Periodicity in Properties - Electron Gain Enthalpy

Grade 11CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

β€’

Electron Gain Enthalpy (DeltaegH\\Delta_{eg}H) is the enthalpy change that occurs when an electron is added to an isolated gaseous atom to form a negative ion: X(g)+eβˆ’β†’Xβˆ’(g)X(g) + e^- \rightarrow X^-(g).

β€’

Depending on the element, the process can be exothermic (negative DeltaegH\\Delta_{eg}H) or endothermic (positive DeltaegH\\Delta_{eg}H). Most elements release energy when they gain an electron.

β€’

Across a period (left to right), DeltaegH\\Delta_{eg}H generally becomes more negative because the atomic radius decreases and the effective nuclear charge (ZeffZ_{eff}) increases, leading to a stronger attraction for the incoming electron.

β€’

Down a group, DeltaegH\\Delta_{eg}H generally becomes less negative because the atomic size increases, and the incoming electron is farther from the nucleus, experiencing less attraction.

β€’

Group 17 (Halogens) have the most negative electron gain enthalpies because they only need one electron to achieve a stable noble gas configuration.

β€’

Noble gases (Group 18) have large positive electron gain enthalpies because the added electron has to enter a higher principal quantum level, creating a highly unstable configuration.

β€’

The DeltaegH\\Delta_{eg}H of ClCl is more negative than that of FF. This is because the 2p2p subshell in FF is very compact, leading to significant inter-electronic repulsion when an electron is added, whereas the 3p3p subshell in ClCl is larger and accommodates the electron more easily.

β€’

Successive electron gain enthalpies: Adding a second electron to a uninegative ion (e.g., Oβˆ’(g)+eβˆ’β†’O2βˆ’(g)O^-(g) + e^- \rightarrow O^{2-}(g)) is always endothermic (DeltaegH>0\\Delta_{eg}H > 0) due to the strong electrostatic repulsion between the negative ion and the incoming electron.

πŸ“Formulae

X(g)+eβˆ’β†’Xβˆ’(g)(Ξ”H=Ξ”egH1)X(g) + e^- \rightarrow X^-(g) \quad (\Delta H = \Delta_{eg}H_1)

Xβˆ’(g)+eβˆ’β†’X2βˆ’(g)(Ξ”H=Ξ”egH2>0)X^-(g) + e^- \rightarrow X^{2-}(g) \quad (\Delta H = \Delta_{eg}H_2 > 0)

πŸ’‘Examples

Problem 1:

Which of the following has the most negative electron gain enthalpy: FF, ClCl, BrBr, or II?

Solution:

ClCl (Chlorine)

Explanation:

While Ξ”egH\Delta_{eg}H generally becomes less negative down the group, ClCl is an exception. FF is very small, and the incoming electron faces high inter-electronic repulsion in the 2p2p shell. In ClCl, the 3p3p orbital is larger, reducing repulsion and making the addition of an electron more exothermic than in FF.

Problem 2:

Explain why the second electron gain enthalpy of Oxygen (O+eβˆ’β†’Oβˆ’O + e^- \rightarrow O^-; Oβˆ’+eβˆ’β†’O2βˆ’O^- + e^- \rightarrow O^{2-}) is positive.

Solution:

Ξ”egH2>0\Delta_{eg}H_2 > 0

Explanation:

The first electron gain involves adding an electron to a neutral atom, which is exothermic. However, the second electron must be added to a negatively charged ion (Oβˆ’O^-). The strong electrostatic repulsion between the negative ion and the incoming electron requires energy to be supplied to overcome the force, making the process endothermic.

Problem 3:

Arrange the following in increasing order of negative electron gain enthalpy: OO, SS, FF, ClCl.

Solution:

O<S<F<ClO < S < F < Cl

Explanation:

Halogens have more negative Ξ”egH\Delta_{eg}H than chalcogens because they are closer to achieving a noble gas configuration. Between OO and SS, SS is more negative due to less electronic repulsion in the 3p3p shell. Similarly, ClCl is more negative than FF.

Electron Gain Enthalpy - Revision Notes & Key Formulas | CBSE Class 11 Chemistry