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Chemical Bonding and Molecular Structure - Kossel-Lewis Approach to Chemical Bonding

Grade 11CBSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Kossel and Lewis developed the electronic theory of valence to explain why atoms combine. They postualted that atoms achieve stability by attaining the nearest noble gas configuration (ns2np6ns^2 np^6).

Lewis Symbols: These are notations where valence electrons are represented as dots surrounding the chemical symbol of the element (e.g., Li\cdot Li, :B˙: \dot{B} \cdot).

Octet Rule: Atoms tend to gain, lose, or share electrons until they are surrounded by eight valence electrons, achieving a stable octet (except Hydrogen, which follows the duplet rule).

Ionic (Electrovalent) Bond: Formed by the complete transfer of one or more electrons from one atom to another, resulting in electrostatic attraction between the formed cations and anions.

Covalent Bond: Formed by the sharing of at least one pair of electrons between two atoms to satisfy the octet rule for both.

Formal Charge: The difference between the number of valence electrons in an isolated atom and the number of electrons assigned to that atom in a Lewis structure.

Limitations of the Octet Rule: It does not account for the 'Incomplete Octet' (e.g., LiClLiCl, BeH2BeH_2, BCl3BCl_3), 'Odd-electron molecules' (e.g., NONO, NO2NO_2), or the 'Expanded Octet' (e.g., PF5PF_5, SF6SF_6, H2SO4H_2SO_4).

📐Formulae

FC=[VL12S]FC = [V - L - \frac{1}{2}S]

where V=Total number of valence electrons in the free atom\text{where } V = \text{Total number of valence electrons in the free atom}

L=Total number of non-bonding (lone pair) electronsL = \text{Total number of non-bonding (lone pair) electrons}

S=Total number of bonding (shared) electronsS = \text{Total number of bonding (shared) electrons}

💡Examples

Problem 1:

Calculate the formal charge of the central oxygen atom in the Ozone (O3O_3) molecule.

Solution:

  1. The Lewis structure of O3O_3 features a central oxygen atom (labeled 1) double-bonded to one oxygen (labeled 2) and single-bonded to another (labeled 3).
  2. For the central atom (1): V=6V = 6, L=2L = 2 (one lone pair), and S=6S = 6 (3 bonds = 6 shared electrons).
  3. FC=6212(6)=623=+1FC = 6 - 2 - \frac{1}{2}(6) = 6 - 2 - 3 = +1.

Explanation:

In the Lewis structure of O3O_3, the central oxygen atom shares three electron pairs with neighboring atoms and retains one lone pair, resulting in a formal charge of +1+1.

Problem 2:

Draw the Lewis representation for the formation of MgCl2MgCl_2.

Solution:

MgMg2++2eMg \rightarrow Mg^{2+} + 2e^- 2Cl+2e2Cl2Cl + 2e^- \rightarrow 2Cl^- [Mg]2+[:Cl¨:]2[Mg]^{2+} [:\ddot{Cl}:]_2^-

Explanation:

Magnesium (valence 3s23s^2) loses two electrons to achieve the Neon configuration, while two Chlorine atoms (valence 3s23p53s^2 3p^5) each gain one electron to achieve the Argon configuration, forming an ionic bond.

Kossel-Lewis Approach to Chemical Bonding Revision - Class 11 Chemistry CBSE