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Reproduction - Sexual Reproduction in Flowering Plants

Grade 12ICSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A flower is a modified shoot where the shoot apical meristem changes to floral meristem. The four whorls are Calyx, Corolla, Androecium, and Gynoecium.

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The Microsporangium (Pollen sac) consists of four wall layers: the epidermis, endothecium, middle layers, and the tapetum which provides nourishment to the developing pollen grains.

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Microsporogenesis is the process of formation of microspores from a Pollen Mother Cell (PMCPMC) through meiosis. Each PMCPMC produces four microspores (nn).

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The Pollen grain represents the male gametophyte. It has a two-layered wall: the outer thick Exine made of sporopollenin (highly resistant) and the inner thin Intine made of cellulose and pectin.

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Megasporogenesis is the formation of megaspores from the Megaspore Mother Cell (MMCMMC). In most flowering plants, only one megaspore remains functional while the other three degenerate.

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The female gametophyte (Embryo Sac) is typically 7-celled and 8-nucleate. It contains the egg apparatus (two synergids and one egg cell), three antipodals, and one large central cell with two polar nuclei.

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Pollination types include Autogamy (same flower), Geitonogamy (different flower, same plant), and Xenogamy (different plant).

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Double Fertilization is a unique event in Angiosperms where one male gamete (nn) fuses with the egg (nn) to form a zygote (2n2n), and the second male gamete (nn) fuses with two polar nuclei (2n2n) to form the Primary Endosperm Nucleus (3n3n).

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The PENPEN develops into the endosperm, which provides nutrition to the developing embryo. Endosperm can be Nuclear, Cellular, or Helobial.

📐Formulae

Number of Meiotic Divisions for x Pollen Grains=x4\text{Number of Meiotic Divisions for } x \text{ Pollen Grains} = \frac{x}{4}

Number of Meiotic Divisions for x Seeds=x+x4=5x4\text{Number of Meiotic Divisions for } x \text{ Seeds} = x + \frac{x}{4} = \frac{5x}{4}

Ploidy of Endosperm=3n\text{Ploidy of Endosperm} = 3n

Ploidy of Zygote=2n\text{Ploidy of Zygote} = 2n

Syngamy (n+n→2n) + Triple Fusion (n+2n→3n) = Double Fertilization\text{Syngamy (} n + n \rightarrow 2n \text{) + Triple Fusion (} n + 2n \rightarrow 3n \text{) = Double Fertilization}

💡Examples

Problem 1:

If the diploid chromosome number of a flowering plant is 2n=242n = 24, determine the number of chromosomes in the following: (a) Pollen grain, (b) Endosperm, (c) Antipodal cell.

Solution:

(a) Pollen grain = 1212, (b) Endosperm = 3636, (c) Antipodal cell = 1212.

Explanation:

Given 2n=242n = 24, the haploid number n=12n = 12. Pollen grains and antipodal cells are haploid (nn), so they have 1212 chromosomes. The endosperm is triploid (3n3n) due to triple fusion, so 3×12=363 \times 12 = 36 chromosomes.

Problem 2:

How many meiotic divisions are required to produce 200200 seeds in a typical Angiosperm?

Solution:

250250 meiotic divisions.

Explanation:

To produce 200200 seeds, 200200 male gametes and 200200 female gametes (eggs) are required. One meiosis in the microspore mother cell produces 44 pollen grains; thus, 200/4=50200/4 = 50 divisions. One meiosis in the megaspore mother cell produces only 11 functional megaspore; thus, 200200 divisions. Total = 50+200=25050 + 200 = 250.