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Reproduction - Sexual Reproduction in Flowering Plants

Grade 12ICSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A flower is a modified shoot where the shoot apical meristem changes to floral meristem. The four whorls are Calyx, Corolla, Androecium, and Gynoecium.

The Microsporangium (Pollen sac) consists of four wall layers: the epidermis, endothecium, middle layers, and the tapetum which provides nourishment to the developing pollen grains.

Microsporogenesis is the process of formation of microspores from a Pollen Mother Cell (PMCPMC) through meiosis. Each PMCPMC produces four microspores (nn).

The Pollen grain represents the male gametophyte. It has a two-layered wall: the outer thick Exine made of sporopollenin (highly resistant) and the inner thin Intine made of cellulose and pectin.

Megasporogenesis is the formation of megaspores from the Megaspore Mother Cell (MMCMMC). In most flowering plants, only one megaspore remains functional while the other three degenerate.

The female gametophyte (Embryo Sac) is typically 7-celled and 8-nucleate. It contains the egg apparatus (two synergids and one egg cell), three antipodals, and one large central cell with two polar nuclei.

Pollination types include Autogamy (same flower), Geitonogamy (different flower, same plant), and Xenogamy (different plant).

Double Fertilization is a unique event in Angiosperms where one male gamete (nn) fuses with the egg (nn) to form a zygote (2n2n), and the second male gamete (nn) fuses with two polar nuclei (2n2n) to form the Primary Endosperm Nucleus (3n3n).

The PENPEN develops into the endosperm, which provides nutrition to the developing embryo. Endosperm can be Nuclear, Cellular, or Helobial.

📐Formulae

Number of Meiotic Divisions for x Pollen Grains=x4\text{Number of Meiotic Divisions for } x \text{ Pollen Grains} = \frac{x}{4}

Number of Meiotic Divisions for x Seeds=x+x4=5x4\text{Number of Meiotic Divisions for } x \text{ Seeds} = x + \frac{x}{4} = \frac{5x}{4}

Ploidy of Endosperm=3n\text{Ploidy of Endosperm} = 3n

Ploidy of Zygote=2n\text{Ploidy of Zygote} = 2n

Syngamy (n+n2n) + Triple Fusion (n+2n3n) = Double Fertilization\text{Syngamy (} n + n \rightarrow 2n \text{) + Triple Fusion (} n + 2n \rightarrow 3n \text{) = Double Fertilization}

💡Examples

Problem 1:

If the diploid chromosome number of a flowering plant is 2n=242n = 24, determine the number of chromosomes in the following: (a) Pollen grain, (b) Endosperm, (c) Antipodal cell.

Solution:

(a) Pollen grain = 1212, (b) Endosperm = 3636, (c) Antipodal cell = 1212.

Explanation:

Given 2n=242n = 24, the haploid number n=12n = 12. Pollen grains and antipodal cells are haploid (nn), so they have 1212 chromosomes. The endosperm is triploid (3n3n) due to triple fusion, so 3×12=363 \times 12 = 36 chromosomes.

Problem 2:

How many meiotic divisions are required to produce 200200 seeds in a typical Angiosperm?

Solution:

250250 meiotic divisions.

Explanation:

To produce 200200 seeds, 200200 male gametes and 200200 female gametes (eggs) are required. One meiosis in the microspore mother cell produces 44 pollen grains; thus, 200/4=50200/4 = 50 divisions. One meiosis in the megaspore mother cell produces only 11 functional megaspore; thus, 200200 divisions. Total = 50+200=25050 + 200 = 250.

Sexual Reproduction in Flowering Plants Revision - Class 12 Biology ICSE