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Genetics and Evolution - Principles of Inheritance and Variation

Grade 12ICSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Mendel's Laws: Includes the Law of Dominance (dominant allele masks recessive), the Law of Segregation (alleles separate during gamete formation), and the Law of Independent Assortment (genes for different traits segregate independently during the formation of gametes).

Incomplete Dominance: A condition where the F1F_1 phenotype does not resemble either parent and is an intermediate, such as the pink flowers in AntirrhinumAntirrhinum majusmajus resulting from a cross between red (RRRR) and white (rrrr) flowers.

Codominance: Occurs when both alleles express themselves fully in the heterozygote, e.g., the ABAB blood group in humans where both IAI^A and IBI^B alleles are dominant.

Multiple Allelism: When more than two alleles govern the same character, such as the ABOABO blood grouping system in humans (IAI^A, IBI^B, and ii).

Pleiotropy: A single gene exhibiting multiple phenotypic expressions, such as Phenylketonuria (PKUPKU) or Sickle-cell anemia.

Polygenic Inheritance: Traits controlled by three or more genes, where the effect of each allele is additive, such as human skin color or height.

Sex Determination: Different mechanisms including XX/XYXX/XY (humans, DrosophilaDrosophila), XX/XOXX/XO (grasshoppers), and ZZ/ZWZZ/ZW (birds, where females are heterogametic).

Mendelian Disorders: Genetic disorders caused by mutation in a single gene, following Mendelian inheritance patterns (e.g., Hemophilia - XX-linked recessive, Sickle-cell anemia - Autosomal recessive).

Chromosomal Disorders: Caused by the absence or excess of one or more chromosomes, such as Down's Syndrome (Trisomy 21: 2n+12n + 1), Klinefelter's Syndrome (47,XXY47, XXY), and Turner's Syndrome (45,XO45, XO).

📐Formulae

Number of gametes produced by a genotype=2n (where n=number of heterozygous loci)\text{Number of gametes produced by a genotype} = 2^n \text{ (where } n = \text{number of heterozygous loci)} patterns

Phenotypic Ratio (Monohybrid Cross)=3:1\text{Phenotypic Ratio (Monohybrid Cross)} = 3:1

Genotypic Ratio (Monohybrid Cross)=1:2:1\text{Genotypic Ratio (Monohybrid Cross)} = 1:2:1

Phenotypic Ratio (Dihybrid Cross)=9:3:3:1\text{Phenotypic Ratio (Dihybrid Cross)} = 9:3:3:1

Recombination Frequency=Number of recombinantsTotal number of offspring×100\text{Recombination Frequency} = \frac{\text{Number of recombinants}}{\text{Total number of offspring}} \times 100

Number of Genotypes in F2 (Dihybrid)=3n=32=9\text{Number of Genotypes in } F_2 \text{ (Dihybrid)} = 3^n = 3^2 = 9

💡Examples

Problem 1:

A man with blood group AA (heterozygous) marries a woman with blood group BB (heterozygous). What are the possible blood groups and their probabilities in their children?

Solution:

The genotype of the man is IAiI^Ai and the woman is IBiI^Bi. The cross (IAi×IBiI^Ai \times I^Bi) yields: 1/41/4 IAIBI^AI^B (Group ABAB), 1/41/4 IAiI^Ai (Group AA), 1/41/4 IBiI^Bi (Group BB), and 1/41/4 iiii (Group OO).

Explanation:

Due to the presence of multiple alleles and codominance, all four blood types are possible with a 25%25\% probability each.

Problem 2:

In a test cross involving a heterozygous tall pea plant (TtTt), what is the expected phenotypic ratio of the offspring?

Solution:

A test cross involves crossing the individual with a homozygous recessive parent: Tt×ttTt \times tt. Gametes from TtTt are TT and tt; gametes from tttt are only tt. Resulting genotypes: TtTt (Tall) and tttt (Dwarf).

Explanation:

The phenotypic and genotypic ratio for a monohybrid test cross is always 1:11:1.

Problem 3:

Calculate the recombination frequency if 100 offspring are produced in a cross, and 15 of them show recombinant phenotypes.

Solution:

Frequency=15100×100=15%\text{Frequency} = \frac{15}{100} \times 100 = 15\%

Explanation:

Recombination frequency is a measure of the distance between genes on a chromosome, where 1%1\% recombination equals 11 centiMorgan (cMcM).

Principles of Inheritance and Variation Revision - Class 12 Biology ICSE