Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Mendel's Laws: Includes the Law of Dominance (dominant allele masks recessive), the Law of Segregation (alleles separate during gamete formation), and the Law of Independent Assortment (genes for different traits segregate independently during the formation of gametes).
Incomplete Dominance: A condition where the phenotype does not resemble either parent and is an intermediate, such as the pink flowers in resulting from a cross between red () and white () flowers.
Codominance: Occurs when both alleles express themselves fully in the heterozygote, e.g., the blood group in humans where both and alleles are dominant.
Multiple Allelism: When more than two alleles govern the same character, such as the blood grouping system in humans (, , and ).
Pleiotropy: A single gene exhibiting multiple phenotypic expressions, such as Phenylketonuria () or Sickle-cell anemia.
Polygenic Inheritance: Traits controlled by three or more genes, where the effect of each allele is additive, such as human skin color or height.
Sex Determination: Different mechanisms including (humans, ), (grasshoppers), and (birds, where females are heterogametic).
Mendelian Disorders: Genetic disorders caused by mutation in a single gene, following Mendelian inheritance patterns (e.g., Hemophilia - -linked recessive, Sickle-cell anemia - Autosomal recessive).
Chromosomal Disorders: Caused by the absence or excess of one or more chromosomes, such as Down's Syndrome (Trisomy 21: ), Klinefelter's Syndrome (), and Turner's Syndrome ().
📐Formulae
patterns
💡Examples
Problem 1:
A man with blood group (heterozygous) marries a woman with blood group (heterozygous). What are the possible blood groups and their probabilities in their children?
Solution:
The genotype of the man is and the woman is . The cross () yields: (Group ), (Group ), (Group ), and (Group ).
Explanation:
Due to the presence of multiple alleles and codominance, all four blood types are possible with a probability each.
Problem 2:
In a test cross involving a heterozygous tall pea plant (), what is the expected phenotypic ratio of the offspring?
Solution:
A test cross involves crossing the individual with a homozygous recessive parent: . Gametes from are and ; gametes from are only . Resulting genotypes: (Tall) and (Dwarf).
Explanation:
The phenotypic and genotypic ratio for a monohybrid test cross is always .
Problem 3:
Calculate the recombination frequency if 100 offspring are produced in a cross, and 15 of them show recombinant phenotypes.
Solution:
Explanation:
Recombination frequency is a measure of the distance between genes on a chromosome, where recombination equals centiMorgan ().