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Nucleic Acids (AHL) - Translation

Grade 12IBBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Translation is the process of protein synthesis where the genetic information encoded in mRNA is translated into a sequence of amino acids. It occurs in the 535' \rightarrow 3' direction.

Ribosomes consist of a small and a large subunit, made of RNA and proteins. They contain three binding sites for tRNA: the AA (aminoacyl) site, the PP (peptidyl) site, and the EE (exit) site.

tRNA activation involves the enzyme tRNA activating enzyme (aminoacyl-tRNA synthetase), which attaches a specific amino acid to the 33' end of the tRNA using energy from ATPATP.

Initiation of translation involves the assembly of the mRNA, the first tRNA (carrying methionine, codon AUGAUG), and the ribosomal subunits.

Elongation is a repeated cycle where new aminoacyl-tRNAs bind to the AA site, a peptide bond forms between amino acids, and the ribosome translocates along the mRNA.

Termination occurs when a stop codon (UAAUAA, UAGUAG, or UGAUGA) is reached. A release factor fills the AA site, leading to the disassembly of the translation complex.

In prokaryotes, translation can occur immediately after transcription because there is no nuclear envelope separating the processes, often forming polysomes (multiple ribosomes on one mRNA).

Protein structure levels: Primary (amino acid sequence), Secondary (α\alpha-helices and β\beta-pleated sheets via HH-bonds), Tertiary (3D3D folding via RR-group interactions), and Quaternary (multiple polypeptide chains).

📐Formulae

Amino Acid+ATP+tRNAtRNA synthetaseAminoacyl-tRNA+AMP+PPiAmino\ Acid + ATP + tRNA \xrightarrow{tRNA\ synthetase} Aminoacyl\text{-}tRNA + AMP + PP_i

Total Nucleotides=(namino acids×3)+3 (stop codon)Total\ Nucleotides = (n_{amino\ acids} \times 3) + 3\ (stop\ codon)

namino acids=nnucleotides in coding region31n_{amino\ acids} = \frac{n_{nucleotides\ in\ coding\ region}}{3} - 1

💡Examples

Problem 1:

A specific mRNA sequence is 450 nucleotides long, including the start and stop codons. Calculate the number of amino acids in the resulting polypeptide chain.

Solution:

149 amino acids.

Explanation:

First, find the total number of codons: 450÷3=150450 \div 3 = 150 codons. Since the final codon is a stop codon (UAAUAA, UAGUAG, or UGAUGA) which does not code for an amino acid, the number of amino acids is 1501=149150 - 1 = 149.

Problem 2:

Explain the role of ATPATP in the formation of the aminoacyl-tRNA complex.

Solution:

ATP+Amino acidAminoacyl-AMP+PPiATP + Amino\ acid \rightarrow Aminoacyl\text{-}AMP + PP_i, then Aminoacyl-AMP+tRNAAminoacyl-tRNA+AMPAminoacyl\text{-}AMP + tRNA \rightarrow Aminoacyl\text{-}tRNA + AMP.

Explanation:

The hydrolysis of ATPATP provides the energy required to covalently bond the amino acid to the 33' end of its specific tRNA. This 'charges' the tRNA, providing the necessary energy for the later formation of a peptide bond during translation elongation.

Translation - Revision Notes & Key Diagrams | IB Grade 12 Biology