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Molecular Biology - Structure of DNA and RNA

Grade 12IBBiology

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Nucleotides are the monomers of nucleic acids, consisting of a pentose sugar, a phosphate group (PO43βˆ’PO_{4}^{3-}), and a nitrogenous base.

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In DNA, the pentose sugar is deoxyribose (C5H10O4C_{5}H_{10}O_{4}), whereas in RNA, it is ribose (C5H10O5C_{5}H_{10}O_{5}), which has a hydroxyl group (βˆ’OH-OH) on the 2β€²2' carbon.

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DNA is double-stranded and forms a double helix, while RNA is typically single-stranded. The two strands of DNA are antiparallel, running in opposite 5β€²β†’3β€²5' \rightarrow 3' and 3β€²β†’5β€²3' \rightarrow 5' directions.

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Nitrogenous bases are categorized into Purines (Adenine AA and Guanine GG) and Pyrimidines (Cytosine CC, Thymine TT, and Uracil UU). In DNA, AA pairs with TT and GG pairs with CC. In RNA, UU replaces TT.

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Nucleotides are linked covalently by phosphodiester bonds between the 3β€²3' hydroxyl group of one sugar and the 5β€²5' phosphate group of the next, creating a sugar-phosphate backbone.

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Hydrogen bonding facilitates complementary base pairing: AA and TT (or UU) form 22 hydrogen bonds, while GG and CC form 33 hydrogen bonds.

πŸ“Formulae

[A]=[T][A] = [T]

[G]=[C][G] = [C]

[A]+[G]=[T]+[C][A] + [G] = [T] + [C]

%A+%T+%G+%C=100%\%A + \%T + \%G + \%C = 100\%

πŸ’‘Examples

Problem 1:

A double-stranded DNA molecule is found to have a Guanine (GG) content of 22%22\%. Calculate the percentage of Adenine (AA) present in this molecule.

Solution:

If G=22%G = 22\%, then by Chargaff's rule, C=22%C = 22\%. The combined total of G+C=22%+22%=44%G + C = 22\% + 22\% = 44\%. The remaining percentage for A+TA + T is 100%βˆ’44%=56%100\% - 44\% = 56\%. Since A=TA = T, the percentage of Adenine is 56%2=28%\frac{56\%}{2} = 28\%.

Explanation:

Chargaff's rule states that in double-stranded DNA, the amount of purines equals the amount of pyrimidines because of specific base pairing (AA with TT and GG with CC).

Problem 2:

Identify the difference in the chemical structure of the sugars found in a DNA nucleotide versus an RNA nucleotide.

Solution:

The sugar in DNA is 2β€²2'-deoxyribose, which has a hydrogen atom (βˆ’H-H) attached to the 2β€²2' carbon. The sugar in RNA is ribose, which has a hydroxyl group (βˆ’OH-OH) attached to the 2β€²2' carbon.

Explanation:

This single oxygen atom difference (C5H10O4C_{5}H_{10}O_{4} vs C5H10O5C_{5}H_{10}O_{5}) affects the stability and folding of the nucleic acid polymers.

Structure of DNA and RNA - Revision Notes & Key Diagrams | IB Grade 12 Biology