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Molecular Biology - Proteins

Grade 12IBBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Proteins are composed of long chains of amino acids linked together by peptide bonds through condensation reactions, where a molecule of H2OH_{2}O is released.

There are 2020 different amino acids used by ribosomes to create polypeptides, each differing by its specific RR group (side chain).

The primary structure of a protein is the specific sequence of amino acids, which is determined by the DNADNA base sequence of the gene.

Secondary structure involves the folding of the polypeptide chain into α\alpha-helices or β\beta-pleated sheets, stabilized by hydrogen bonds between the NH-NH and C=O-C=O groups.

Tertiary structure is the further 3D3D folding of the protein caused by interactions between RR groups, including disulfide bridges, ionic bonds, hydrogen bonds, and hydrophobic interactions.

Quaternary structure exists in proteins consisting of more than one polypeptide chain, such as Hemoglobin (44 subunits) or Collagen (33 subunits).

The proteome is the entire set of proteins expressed by a genome, cell, tissue, or organism at a given time and is unique to every individual.

Denaturation is a structural change in a protein that results in the loss of its biological properties, typically caused by high temperatures or deviations from the optimum pHpH.

Key examples of proteins include: Rubisco (enzyme for CO2CO_{2} fixation), Insulin (hormone for glucose uptake), Immunoglobulins (antibodies), and Rhodopsin (light-sensitive pigment).

📐Formulae

npeptide bonds=namino acids1n_{peptide\ bonds} = n_{amino\ acids} - 1

Possible sequences=20n\text{Possible sequences} = 20^{n}

C106H168N26O30S2 (Example empirical formula for a small protein segment)C_{106}H_{168}N_{26}O_{30}S_{2} \text{ (Example empirical formula for a small protein segment)}

RCH(NH2)COOH (General formula of an amino acid)R-CH(NH_{2})-COOH \text{ (General formula of an amino acid)}

💡Examples

Problem 1:

Calculate the total number of possible amino acid sequences for a polypeptide that is 55 amino acids long.

Solution:

205=3,200,00020^{5} = 3,200,000

Explanation:

Since there are 2020 different standard amino acids that can occupy any of the 55 positions in the chain, the total number of permutations is calculated as 2020 raised to the power of the number of amino acids (nn).

Problem 2:

Explain how a change in pHpH can lead to the denaturation of a globular protein.

Solution:

A change in pHpH alters the charge of the RR groups, which disrupts the ionic bonds and hydrogen bonds that stabilize the tertiary structure.

Explanation:

The 3D3D shape (tertiary structure) of a protein is held together by various R-group interactions. H+H^{+} and OHOH^{-} ions interfere with the electrostatic attractions (ionic bonds) and HH-bonding, causing the protein to unfold and lose its functional site.

Proteins - Revision Notes & Key Diagrams | IB Grade 12 Biology