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Cell Biology - Introduction to cells

Grade 12IBBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Cell Theory states: 1. All living organisms are composed of cells. 2. The cell is the smallest unit of life. 3. Cells arise from pre-existing cells.

Exceptions to the Cell Theory include: Striated muscle fibers (multiple nuclei in a single cell), Aseptate fungal hyphae (lacks septa/walls separating nuclei), and Giant Algae (AcetabulariaAcetabularia, which is a very large single cell with one nucleus).

All organisms perform the seven functions of life: Metabolism, Reproduction, Homeostasis, Growth, Response, Excretion, and Nutrition (MR H GRENMR\ H\ GREN).

The Surface Area to Volume ratio (SA:VolSA:Vol) limits cell size. As a cell grows, volume increases at a rate of x3x^3 while surface area increases at x2x^2. If the ratio is too small, substances cannot enter/exit quickly enough to sustain metabolic needs.

Multicellular organisms show emergent properties: 'The whole is greater than the sum of its parts,' meaning interaction between individual components produces new, complex functions.

Differentiation involves the expression of some genes and not others in a cell's genome to develop specialized tissues.

Stem cells are characterized by their capacity to divide indefinitely and their potency to differentiate into specialized cell types. They are used to treat StargardtsStargardt's disease (replacing retinal cells) and Leukemia (replacing white blood cells).

📐Formulae

Magnification=Measured size of imageActual size of specimen\text{Magnification} = \frac{\text{Measured size of image}}{\text{Actual size of specimen}}

Actual Size=Measured size of imageMagnification\text{Actual Size} = \frac{\text{Measured size of image}}{\text{Magnification}}

1 mm=103 μm=106 nm1\text{ mm} = 10^3\ \mu m = 10^6\text{ nm}

Surface Area (cube)=6L2\text{Surface Area (cube)} = 6L^2

Volume (cube)=L3\text{Volume (cube)} = L^3

💡Examples

Problem 1:

A micrograph shows a mitochondrion with a length of 40 mm40\text{ mm}. If the scale bar on the image indicates a magnification of 50,000×50,000\times, calculate the actual size of the mitochondrion in micrometers (μm\mu m).

Solution:

0.8 μm0.8\ \mu m

Explanation:

Using the formula Actual Size=Image SizeMagnification\text{Actual Size} = \frac{\text{Image Size}}{\text{Magnification}}. First, convert the image size to micrometers: 40 mm×1000=40,000 μm40\text{ mm} \times 1000 = 40,000\ \mu m. Then divide by magnification: 40,000 μm50,000=0.8 μm\frac{40,000\ \mu m}{50,000} = 0.8\ \mu m.

Problem 2:

A cube-shaped cell has a side length of 10 μm10\ \mu m. Calculate its SA:VolSA:Vol ratio.

Solution:

0.6 μm10.6\ \mu m^{-1}

Explanation:

Surface Area (SASA) =6×(10 μm)2=600 μm2= 6 \times (10\ \mu m)^2 = 600\ \mu m^2. Volume (VV) =(10 μm)3=1000 μm3= (10\ \mu m)^3 = 1000\ \mu m^3. Ratio =6001000=0.6= \frac{600}{1000} = 0.6.

Introduction to cells - Revision Notes & Key Diagrams | IB Grade 12 Biology