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Respiration - Aerobic respiration

Grade 11A LevelBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Aerobic respiration is defined as the chemical reactions in cells that use oxygen to break down nutrient molecules to release a relatively large amount of energy.

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The primary nutrient molecule used is glucose, which has the chemical formula C6H12O6C_6H_{12}O_6.

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The process involves a series of enzyme-controlled reactions that occur in the cytoplasm (glycolysis) and primarily within the mitochondria.

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The energy released is stored in the form of ATPATP (adenosine triphosphate), which powers cellular processes like protein synthesis, muscle contraction, and active transport.

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The waste products of aerobic respiration are carbon dioxide (CO2CO_2) and water (H2OH_2O), which must be excreted from the organism.

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Aerobic respiration is much more efficient than anaerobic respiration, yielding significantly more energy per molecule of glucose (approximately 2880 kJ/mol2880\ kJ/mol).

📐Formulae

Glucose+Oxygen→Carbon dioxide+Water(+Energy)Glucose + Oxygen \rightarrow Carbon\ dioxide + Water (+ Energy)

C6H12O6+6O2→6CO2+6H2OC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O

💡Examples

Problem 1:

Calculate the total number of oxygen (O2O_2) molecules required to completely respire 55 molecules of glucose (C6H12O6C_6H_{12}O_6) aerobically.

Solution:

3030 molecules of O2O_2

Explanation:

According to the balanced chemical equation C6H12O6+6O2→6CO2+6H2OC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O, the molar ratio of glucose to oxygen is 1:61:6. Therefore, for 55 molecules of glucose, the oxygen required is 5×6=305 \times 6 = 30 molecules.

Problem 2:

Identify the number of carbon dioxide molecules produced when 0.5 mol0.5\ mol of glucose is used in aerobic respiration.

Solution:

3.0 mol3.0\ mol of CO2CO_2

Explanation:

Based on the equation C6H12O6+6O2→6CO2+6H2OC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O, one mole of glucose produces 66 moles of CO2CO_2. Thus, 0.5 mol×6=3.0 mol0.5\ mol \times 6 = 3.0\ mol of CO2CO_2.