krit.club logo

Organisms and their Environment - Energy flow and food webs

Grade 11IGCSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Sun is the principal source of energy input to biological systems, where light energy is captured by producers during photosynthesis to create chemical energy in the form of C6H12O6C_6H_{12}O_6.

Energy flow is linear and non-cyclical; it enters ecosystems as light and is eventually lost to the environment as heat energy.

A food chain shows the transfer of energy from one organism to the next, beginning with a producer (Trophic Level 1).

Food webs are networks of interconnected food chains, representing the complex feeding relationships within an ecosystem.

Energy is lost at each trophic level through metabolic processes such as aerobic respiration (C6H12O6+6O26CO2+6H2O+energyC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + \text{energy}), excretion, and as heat.

Only approximately 10%10\% of the energy from one trophic level is passed to the next, which limits the number of trophic levels in a food chain to usually no more than five.

Pyramids of numbers represent the count of individuals at each level, while Pyramids of Biomass represent the dry mass of living material (g/m2g/m^2). Pyramids of Energy represent the total energy available (kJ/m2/yearkJ/m^2/year) and are always upright.

Decomposers (fungi and bacteria) play a vital role by breaking down dead organic matter and returning nutrients to the soil, though the energy they extract is also eventually lost as heat.

📐Formulae

Efficiency of Energy Transfer=Energy available after transferEnergy available before transfer×100%\text{Efficiency of Energy Transfer} = \frac{\text{Energy available after transfer}}{\text{Energy available before transfer}} \times 100\%

6CO2+6H2Olight, chlorophyllC6H12O6+6O26CO_2 + 6H_2O \xrightarrow{\text{light, chlorophyll}} C_6H_{12}O_6 + 6O_2

C6H12O6+6O26CO2+6H2O+EnergyC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + \text{Energy}

💡Examples

Problem 1:

In a simple food chain: Grass \rightarrow Grasshopper \rightarrow Frog \rightarrow Snake. If the Grass produces 50,000 kJ50,000\text{ kJ} of energy, calculate the energy available to the Snake, assuming a 10%10\% efficiency of transfer at each step.

Solution:

50 kJ50\text{ kJ}

Explanation:

Energy at Trophic Level 1 (Grass) = 50,000 kJ50,000\text{ kJ}. At Trophic Level 2 (Grasshopper), energy = 50,000×0.10=5,000 kJ50,000 \times 0.10 = 5,000\text{ kJ}. At Trophic Level 3 (Frog), energy = 5,000×0.10=500 kJ5,000 \times 0.10 = 500\text{ kJ}. At Trophic Level 4 (Snake), energy = 500×0.10=50 kJ500 \times 0.10 = 50\text{ kJ}.

Problem 2:

A field of wheat contains 8,000 kg8,000\text{ kg} of biomass. The locusts consuming the wheat have a total biomass of 800 kg800\text{ kg}. Calculate the efficiency of biomass transfer from the wheat to the locusts.

Solution:

10%10\%

Explanation:

Using the efficiency formula: 800 kg8,000 kg×100=10%\frac{800\text{ kg}}{8,000\text{ kg}} \times 100 = 10\%. This follows the general ecological rule that roughly 90%90\% of biomass/energy is lost between levels.

Energy flow and food webs - Revision Notes & Key Diagrams | IGCSE Grade 11 Biology