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Inheritance - Chromosomes, genes and proteins

Grade 11IGCSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Chromosomes are thread-like structures of DNADNA, carrying genetic information in the form of genes, located in the nucleus of cells.

A gene is a length of DNADNA that codes for a specific protein. The sequence of bases in the DNADNA determines the sequence of amino acids in that protein.

Alleles are alternative forms of a particular gene (e.g., AA vs aa).

In a diploid cell, chromosomes come in pairs. The human diploid number is 2n=462n = 46.

Haploid cells, such as gametes (sperm and egg), contain only one set of chromosomes. In humans, the haploid number is n=23n = 23.

The DNADNA molecule is a double helix consisting of two strands held together by complementary base pairs: Adenine (AA) with Thymine (TT), and Cytosine (CC) with Guanine (GG).

Protein synthesis involves the transcription of DNADNA into mRNAmRNA in the nucleus, followed by the translation of mRNAmRNA into a polypeptide chain at the ribosome.

A sequence of three bases in mRNAmRNA, called a codon, codes for one specific amino acid.

📐Formulae

2n=diploid number2n = \text{diploid number}

n=haploid numbern = \text{haploid number}

Base Pairs: AT,CG\text{Base Pairs: } A-T, C-G

3 bases=1 amino acid (codon)3 \text{ bases} = 1 \text{ amino acid (codon)}

💡Examples

Problem 1:

If a species has a diploid chromosome number of 2n=242n = 24, determine the number of chromosomes found in its pollen grain.

Solution:

n=12n = 12

Explanation:

Pollen grains are plant gametes and are therefore haploid. Since the diploid number is 2424, the haploid number is calculated as 242=12\frac{24}{2} = 12.

Problem 2:

A segment of DNADNA has the base sequence GCTAGAG-C-T-A-G-A. Determine the complementary sequence on the opposite DNADNA strand.

Solution:

CGATCTC-G-A-T-C-T

Explanation:

According to the base-pairing rules, GG pairs with CC and AA pairs with TT.

Problem 3:

Calculate the number of nitrogenous bases required to code for a protein consisting of 150150 amino acids.

Solution:

450 bases450 \text{ bases}

Explanation:

Each amino acid is coded for by a triplet of bases (a codon). Therefore, 150×3=450150 \times 3 = 450 bases are required (excluding start/stop codons for simplicity).

Chromosomes, genes and proteins - Revision Notes & Key Diagrams | IGCSE Grade 11 Biology