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Excretion in Humans - Excretory products

Grade 11IGCSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Excretion is the removal from organisms of the waste products of metabolism (chemical reactions in cells including respiration), toxic materials, and substances in excess of requirements.

The lungs excrete carbon dioxide (CO2CO_2), which is a waste product of aerobic respiration: C6H12O6+6O26CO2+6H2OC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O.

The kidneys excrete urea, excess salts, and excess water (H2OH_2O). These are passed out of the body in the form of urine.

Urea is produced in the liver from the breakdown of excess amino acids through a process called deamination. The nitrogen-containing part of the amino acid is converted into ammonia (NH3NH_3) and then into the less toxic urea (CO(NH2)2CO(NH_2)_2).

It is important to distinguish between excretion and egestion; egestion is the removal of undigested food (feces) that has never entered the cells or participated in metabolism.

Accumulation of CO2CO_2 in the body is dangerous because it dissolves in blood plasma to form carbonic acid (H2CO3H_2CO_3), which lowers the pHpH and can denature enzymes.

📐Formulae

C6H12O6+6O26CO2+6H2O+EnergyC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + \text{Energy}

CO(NH2)2CO(NH_2)_2

NH3NH_3

CO2+H2OH2CO3H++HCO3CO_2 + H_2O \rightleftharpoons H_2CO_3 \rightleftharpoons H^+ + HCO_3^-

💡Examples

Problem 1:

Identify the excretory organ responsible for the removal of urea and state the metabolic process that produces urea.

Solution:

The excretory organ is the kidney. Urea is produced in the liver via the process of deamination of excess amino acids.

Explanation:

Urea (CO(NH2)2CO(NH_2)_2) is the primary nitrogenous waste in humans. While produced in the liver, it is filtered from the blood and excreted by the kidneys.

Problem 2:

Calculate the amount of water excreted if a person consumes 2500 cm32500\text{ cm}^3 of H2OH_2O, loses 500 cm3500\text{ cm}^3 through sweat and 400 cm3400\text{ cm}^3 through exhalation, assuming they stay in water balance and produce 300 cm3300\text{ cm}^3 of metabolic water.

Solution:

Total H2OH_2O in = 2500+300=2800 cm32500 + 300 = 2800\text{ cm}^3. Total H2OH_2O out = 500+400+Urine500 + 400 + \text{Urine}. For balance: 2800=900+Urine2800 = 900 + \text{Urine}. Urine=1900 cm3\text{Urine} = 1900\text{ cm}^3.

Explanation:

Water balance involves equating the total water intake and metabolic production to the total output through skin, lungs, and kidneys.

Excretory products - Revision Notes & Key Diagrams | IGCSE Grade 11 Biology