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Excretion in Humans - Excretory products

Grade 11A LevelBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Excretion is the removal from organisms of the waste products of metabolism (chemical reactions in cells including respiration), toxic materials, and substances in excess of requirements.

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The lungs excrete carbon dioxide (CO2CO_2), which is a waste product of aerobic respiration: C6H12O6+6O2→6CO2+6H2OC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O.

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The kidneys excrete urea, excess salts, and excess water (H2OH_2O). These are passed out of the body in the form of urine.

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Urea is produced in the liver from the breakdown of excess amino acids through a process called deamination. The nitrogen-containing part of the amino acid is converted into ammonia (NH3NH_3) and then into the less toxic urea (CO(NH2)2CO(NH_2)_2).

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It is important to distinguish between excretion and egestion; egestion is the removal of undigested food (feces) that has never entered the cells or participated in metabolism.

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Accumulation of CO2CO_2 in the body is dangerous because it dissolves in blood plasma to form carbonic acid (H2CO3H_2CO_3), which lowers the pHpH and can denature enzymes.

📐Formulae

C6H12O6+6O2→6CO2+6H2O+EnergyC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + \text{Energy}

CO(NH2)2CO(NH_2)_2

NH3NH_3

CO2+H2O⇌H2CO3⇌H++HCO3−CO_2 + H_2O \rightleftharpoons H_2CO_3 \rightleftharpoons H^+ + HCO_3^-

💡Examples

Problem 1:

Identify the excretory organ responsible for the removal of urea and state the metabolic process that produces urea.

Solution:

The excretory organ is the kidney. Urea is produced in the liver via the process of deamination of excess amino acids.

Explanation:

Urea (CO(NH2)2CO(NH_2)_2) is the primary nitrogenous waste in humans. While produced in the liver, it is filtered from the blood and excreted by the kidneys.

Problem 2:

Calculate the amount of water excreted if a person consumes 2500 cm32500\text{ cm}^3 of H2OH_2O, loses 500 cm3500\text{ cm}^3 through sweat and 400 cm3400\text{ cm}^3 through exhalation, assuming they stay in water balance and produce 300 cm3300\text{ cm}^3 of metabolic water.

Solution:

Total H2OH_2O in = 2500+300=2800 cm32500 + 300 = 2800\text{ cm}^3. Total H2OH_2O out = 500+400+Urine500 + 400 + \text{Urine}. For balance: 2800=900+Urine2800 = 900 + \text{Urine}. Urine=1900 cm3\text{Urine} = 1900\text{ cm}^3.

Explanation:

Water balance involves equating the total water intake and metabolic production to the total output through skin, lungs, and kidneys.