Plant Physiology - Respiration in Plants (Glycolysis, Krebs Cycle, ETS, Amphibolic Pathway)
Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Cellular Respiration is the mechanism of breaking down food materials within the cell to release energy, and the trapping of this energy for synthesis of .
Glycolysis, also known as the EMP pathway, occurs in the cytoplasm. One molecule of glucose () is broken down into two molecules of pyruvic acid () with a net gain of and .
The Link Reaction involves the oxidative decarboxylation of pyruvate into Acetyl in the mitochondrial matrix, mediated by the enzyme pyruvate dehydrogenase, producing and .
The Krebs Cycle (TCA Cycle) occurs in the mitochondrial matrix. It starts with the condensation of Acetyl () with Oxaloacetic acid () to form Citric acid (). For every turn, , , and are produced.
The Electron Transport System (ETS) is located on the inner mitochondrial membrane (cristae). It involves the transfer of electrons through complexes I to IV, eventually reducing to .
Oxidative Phosphorylation is the process of synthesis driven by the proton gradient across the inner mitochondrial membrane, catalyzed by Complex V ( synthase/ particles).
Respiration is considered an Amphibolic Pathway because it involves both catabolism (breakdown of substrates) and anabolism (intermediates like -ketoglutaric acid are used for synthesis of amino acids).
Respiratory Quotient () depends on the type of respiratory substrate used. for carbohydrates, for fats/proteins, and for organic acids.
📐Formulae
💡Examples
Problem 1:
Calculate the Respiratory Quotient () for the fatty acid Tripalmitin ().
Solution:
The balanced equation is: . Therefore, .
Explanation:
Since fats are oxygen-poor compared to carbohydrates, they require more oxygen from the environment for complete oxidation, resulting in an less than unity (1).
Problem 2:
Determine the net gain of when one molecule of Glucose is completely oxidized via aerobic respiration, assuming the malate-aspartate shuttle is used.
Solution:
- Glycolysis: (direct) + () = . 2. Link Reaction: (). 3. Krebs Cycle: (direct) + () + () = . Total: .
Explanation:
In aerobic respiration, and are oxidized via the ETS. The total yield can be or depending on the shuttle system used to transport cytoplasmic into the mitochondria.