Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Cell respiration is the controlled release of energy from organic compounds to produce . In AHL, this focus shifts to the specific redox reactions: Oxidation (loss of electrons/) and Reduction (gain of electrons/).
Phosphorylation is the addition of a phosphate group () to an organic molecule, which makes the molecule less stable and more likely to react. This occurs during the initial stages of Glycolysis ().
Glycolysis occurs in the cytosol. One molecule of glucose () is broken down into two molecules of pyruvate (), with a net yield of and .
The Link Reaction occurs in the mitochondrial matrix. Pyruvate is decarboxylated (removes ) and oxidized (forms ) to produce an acetyl group, which attaches to Coenzyme A to form .
The Krebs Cycle involves the oxidation of acetyl groups. For every turn of the cycle, are released, are produced, is produced, and is generated via substrate-level phosphorylation.
The Electron Transport Chain (ETC) is located on the inner mitochondrial membrane (cristae). Electrons from and are passed through carriers, releasing energy used to pump protons () into the intermembrane space.
Chemiosmosis is the process where the gradient drives synthesis as protons flow back into the matrix through synthase. Oxygen () acts as the final electron acceptor, forming .
Mitochondrial structure is adapted to function: the small intermembrane space allows for rapid build-up of concentration, and the folded cristae increase surface area for the ETC.
📐Formulae
💡Examples
Problem 1:
Calculate the total number of reduced coenzymes ( and ) produced during the complete aerobic respiration of one molecule of glucose, starting from the Link Reaction through to the end of the Krebs Cycle.
Solution:
and .
Explanation:
One glucose molecule produces two pyruvates. The Link Reaction produces per pyruvate ( total). The Krebs Cycle produces and per turn ( and total for two turns). Total: and .
Problem 2:
Explain the role of the proton () gradient in the intermembrane space and how its dissipation leads to production.
Solution:
The gradient represents stored potential energy. As ions move down their electrochemical gradient through the enzyme synthase, the energy is harnessed to phosphorylate .
Explanation:
The ETC pumps into the narrow intermembrane space, creating a high concentration ( ). This 'proton motive force' drives the rotation of synthase (chemiosmosis), which catalyzes the reaction .