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Genetics - Meiosis

Grade 11IBBiology

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Meiosis is a reduction division from a diploid (2n2n) nucleus to four haploid (nn) nuclei, occurring in two stages: Meiosis I and Meiosis II.

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During Prophase I, homologous chromosomes undergo synapsis to form bivalents (tetrads). Crossing over occurs between non-sister chromatids at points called chiasmata, resulting in the exchange of genetic material.

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In Metaphase I, homologous pairs align at the equatorial plate. Their orientation is random, leading to independent assortment of maternal and paternal chromosomes. The number of possible combinations is 2n2^n.

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In Anaphase I, homologous chromosomes are separated and pulled to opposite poles, reducing the chromosome number from 2n2n to nn.

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Meiosis II resembles mitosis, where sister chromatids are separated during Anaphase II, resulting in four genetically distinct haploid (nn) cells.

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Non-disjunction is the failure of chromosomes to separate properly during Anaphase I or II. This leads to aneuploidy, such as Trisomy 21 (Down Syndrome), where an individual has 2n+1=472n + 1 = 47 chromosomes.

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Genetic variation is promoted by three main mechanisms: crossing over in Prophase I, random orientation in Metaphase I, and the random fusion of gametes during fertilization.

πŸ“Formulae

2n2^n

2n→n2n \rightarrow n

n+1Β orΒ nβˆ’1n + 1 \text{ or } n - 1

πŸ’‘Examples

Problem 1:

A cell from an organism with a diploid number of 2n=122n = 12 undergoes meiosis. Calculate the number of possible chromosome combinations in the gametes due to independent assortment alone, assuming no crossing over occurs.

Solution:

The haploid number is n=122=6n = \frac{12}{2} = 6. The number of combinations is 26=642^6 = 64.

Explanation:

Independent assortment occurs during Metaphase I. The number of ways nn pairs of homologous chromosomes can align is given by the formula 2n2^n.

Problem 2:

In a human cell (2n=462n = 46), non-disjunction occurs during Meiosis I for chromosome 21. Describe the resulting gametes.

Solution:

Two gametes will contain n+1=24n + 1 = 24 chromosomes (two copies of chromosome 21), and two gametes will contain nβˆ’1=22n - 1 = 22 chromosomes (zero copies of chromosome 21).

Explanation:

When non-disjunction occurs in Meiosis I, the homologous pair fails to separate. Consequently, all four daughter cells are affected: half have an extra chromosome and half are missing one.

Meiosis - Revision Notes & Key Diagrams | IB Grade 11 Biology