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Photosynthesis in Higher Plants - Photosynthesis as a means of Autotrophic nutrition

Grade 11CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Photosynthesis is a physico-chemical process by which green plants use light energy to synthesize organic compounds. It is the basis of autotrophic nutrition in the biosphere.

The overall process occurs in the chloroplasts. The membranous system (grana) is responsible for the light reaction (trapping light energy and synthesizing ATPATP and NADPHNADPH), while the stroma is the site for the dark reaction (enzymatic reduction of CO2CO_{2} into sugar).

Photosynthetic pigments include Chlorophyll aa (bright or blue-green), Chlorophyll bb (yellow-green), Xanthophylls (yellow), and Carotenoids (yellow to yellow-orange). Chlorophyll aa is the primary pigment acting as the reaction center.

The 'Absorption Spectrum' shows the ability of pigments to absorb light at different wavelengths, while the 'Action Spectrum' indicates the rate of photosynthesis at different wavelengths of light.

Photosynthesis is a redox process where water (H2OH_{2}O) is oxidized to oxygen (O2O_{2}) and carbon dioxide (CO2CO_{2}) is reduced to carbohydrates (C6H12O6C_{6}H_{12}O_{6}).

The Light Harvesting Complex (LHC) consists of hundreds of pigment molecules bound to proteins, forming Photosystem I (PS IPS\ I) and Photosystem II (PS IIPS\ II), named in the sequence of their discovery.

📐Formulae

6CO2+12H2OChlorophyllLightC6H12O6+6H2O+6O26CO_{2} + 12H_{2}O \xrightarrow[Chlorophyll]{Light} C_{6}H_{12}O_{6} + 6H_{2}O + 6O_{2} \uparrow

2H2O4H++O2+4e2H_{2}O \rightarrow 4H^{+} + O_{2} + 4e^{-}

NADP++2e+H+NADP reductaseNADPHNADP^{+} + 2e^{-} + H^{+} \xrightarrow{NADP\ reductase} NADPH

ADP+iP+EnergyATPADP + iP + \text{Energy} \rightarrow ATP

💡Examples

Problem 1:

During the light reaction of photosynthesis, how many molecules of water must be photolysed to release one molecule of oxygen (O2O_{2})?

Solution:

2 molecules of H2OH_{2}O.

Explanation:

According to the photolysis equation 2H2O4H++O2+4e2H_{2}O \rightarrow 4H^{+} + O_{2} + 4e^{-}, two molecules of water are required to generate one molecule of oxygen gas.

Problem 2:

If a plant fixes 6 molecules of CO2CO_{2} through the C3C_{3} pathway (Calvin Cycle), calculate the total number of ATPATP and NADPHNADPH molecules consumed.

Solution:

18 ATP18\ ATP and 12 NADPH12\ NADPH.

Explanation:

For the fixation of one molecule of CO2CO_{2} in the C3C_{3} cycle, 33 molecules of ATPATP and 22 molecules of NADPHNADPH are required. Therefore, for 66 molecules of CO2CO_{2} (to form one glucose molecule): 6×3=18 ATP6 \times 3 = 18\ ATP and 6×2=12 NADPH6 \times 2 = 12\ NADPH.