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Biomolecules - Structure and function of Proteins, Carbohydrates, Lipids, Nucleic acids

Grade 11CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Biomacromolecules are large organic compounds with molecular weights exceeding 10001000 Daltons, found in the acid-insoluble fraction during chemical analysis.

Carbohydrates are polyhydroxy aldehydes or ketones. Monosaccharides are linked by glycosidic bonds formed by dehydration synthesis between two carbon atoms (usually C1C_1 and C4C_4).

Proteins are heteropolymers of amino acids. Each amino acid contains an amino group (NH2-NH_2), a carboxyl group (COOH-COOH), and a variable RR group attached to the α\alpha-carbon.

Protein structure levels: Primary (linear sequence), Secondary (α\alpha-helix or β\beta-pleated sheets via HH-bonds), Tertiary (3D folding via disulfide bridges and ionic bonds), and Quaternary (assembly of multiple polypeptide chains).

Lipids are generally water-insoluble and include fatty acids and glycerol. Triglycerides are formed by the esterification of three fatty acids to one glycerol molecule via ester bonds.

Nucleic acids (DNA and RNA) are polymers of nucleotides. Each nucleotide consists of a pentose sugar, a nitrogenous base, and a phosphate group linked by phosphodiester bonds.

In DNA, the nitrogenous bases follow Chargaff's rule where Purines (A,GA, G) always pair with Pyrimidines (T,CT, C) through hydrogen bonds (A=TA=T and GCG\equiv C).

📐Formulae

Cn(H2O)n (General formula for carbohydrates)C_n(H_2O)_n \text{ (General formula for carbohydrates)}

NH2CH(R)COOH (General structure of an amino acid)NH_2-CH(R)-COOH \text{ (General structure of an amino acid)}

R1COOH+H2NR2R1CONHR2+H2O (Peptide bond formation)R_1-COOH + H_2N-R_2 \rightarrow R_1-CO-NH-R_2 + H_2O \text{ (Peptide bond formation)}

AT=GC=1 (Chargaff’s Rule)\frac{A}{T} = \frac{G}{C} = 1 \text{ (Chargaff's Rule)}

Glycerol+3×Fatty AcidsTriglyceride+3H2O (Esterification)\text{Glycerol} + 3 \times \text{Fatty Acids} \rightarrow \text{Triglyceride} + 3H_2O \text{ (Esterification)}

💡Examples

Problem 1:

A double-stranded DNA molecule has 30%30\% Adenine (AA). Calculate the percentage of Cytosine (CC) present in the molecule.

Solution:

According to Chargaff's Rule, A=TA = T and G=CG = C. If A=30%A = 30\%, then T=30%T = 30\%. Total A+T=60%A + T = 60\%. The remaining 40%40\% must be G+CG + C. Since G=CG = C, then C=40%2=20%C = \frac{40\%}{2} = 20\%.

Explanation:

In DNA, base pairing is specific; hence the molar ratio of purines to pyrimidines is always 1:11:1.

Problem 2:

How many peptide bonds are present in a linear polypeptide chain consisting of 5050 amino acids?

Solution:

n1=501=49n - 1 = 50 - 1 = 49 peptide bonds.

Explanation:

A peptide bond is formed between the carboxyl group of one amino acid and the amino group of the next. For a linear chain of nn monomers, the number of bonds is always n1n-1.

Structure and function of Proteins, Carbohydrates, Lipids, Nucleic acids Revision - Class 11…