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Biomolecules - Structure and function of Proteins, Carbohydrates, Lipids, Nucleic acids

Grade 11CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Biomacromolecules are large organic compounds with molecular weights exceeding 10001000 Daltons, found in the acid-insoluble fraction during chemical analysis.

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Carbohydrates are polyhydroxy aldehydes or ketones. Monosaccharides are linked by glycosidic bonds formed by dehydration synthesis between two carbon atoms (usually C1C_1 and C4C_4).

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Proteins are heteropolymers of amino acids. Each amino acid contains an amino group (−NH2-NH_2), a carboxyl group (−COOH-COOH), and a variable RR group attached to the α\alpha-carbon.

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Protein structure levels: Primary (linear sequence), Secondary (α\alpha-helix or β\beta-pleated sheets via HH-bonds), Tertiary (3D folding via disulfide bridges and ionic bonds), and Quaternary (assembly of multiple polypeptide chains).

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Lipids are generally water-insoluble and include fatty acids and glycerol. Triglycerides are formed by the esterification of three fatty acids to one glycerol molecule via ester bonds.

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Nucleic acids (DNA and RNA) are polymers of nucleotides. Each nucleotide consists of a pentose sugar, a nitrogenous base, and a phosphate group linked by phosphodiester bonds.

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In DNA, the nitrogenous bases follow Chargaff's rule where Purines (A,GA, G) always pair with Pyrimidines (T,CT, C) through hydrogen bonds (A=TA=T and G≡CG\equiv C).

📐Formulae

Cn(H2O)n (General formula for carbohydrates)C_n(H_2O)_n \text{ (General formula for carbohydrates)}

NH2−CH(R)−COOH (General structure of an amino acid)NH_2-CH(R)-COOH \text{ (General structure of an amino acid)}

R1−COOH+H2N−R2→R1−CO−NH−R2+H2O (Peptide bond formation)R_1-COOH + H_2N-R_2 \rightarrow R_1-CO-NH-R_2 + H_2O \text{ (Peptide bond formation)}

AT=GC=1 (Chargaff’s Rule)\frac{A}{T} = \frac{G}{C} = 1 \text{ (Chargaff's Rule)}

Glycerol+3×Fatty Acids→Triglyceride+3H2O (Esterification)\text{Glycerol} + 3 \times \text{Fatty Acids} \rightarrow \text{Triglyceride} + 3H_2O \text{ (Esterification)}

💡Examples

Problem 1:

A double-stranded DNA molecule has 30%30\% Adenine (AA). Calculate the percentage of Cytosine (CC) present in the molecule.

Solution:

According to Chargaff's Rule, A=TA = T and G=CG = C. If A=30%A = 30\%, then T=30%T = 30\%. Total A+T=60%A + T = 60\%. The remaining 40%40\% must be G+CG + C. Since G=CG = C, then C=40%2=20%C = \frac{40\%}{2} = 20\%.

Explanation:

In DNA, base pairing is specific; hence the molar ratio of purines to pyrimidines is always 1:11:1.

Problem 2:

How many peptide bonds are present in a linear polypeptide chain consisting of 5050 amino acids?

Solution:

n−1=50−1=49n - 1 = 50 - 1 = 49 peptide bonds.

Explanation:

A peptide bond is formed between the carboxyl group of one amino acid and the amino group of the next. For a linear chain of nn monomers, the number of bonds is always n−1n-1.