Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Chemical Analysis: Living tissues are analyzed by grinding in trichloroacetic acid (). This separates them into an acid-soluble pool (biomicromolecules with molecular weights to Daltons) and an acid-insoluble fraction (biomacromolecules with weights Daltons).
Amino Acids: These are substituted methanes containing an amino group (), a carboxyl group (), and a variable side chain (). At a specific , they exist as Zwitterions: .
Proteins: Heteropolymers of amino acids linked by peptide bonds (). They exhibit four levels of structure: Primary (sequence), Secondary (-helix, -sheets), Tertiary (3D folding/functionality), and Quaternary (assembly of subunits).
Lipids: Water-insoluble molecules, not strictly polymers. They include fatty acids () and glycerol (). Phospholipids like Lecithin are vital components of the cell membrane.
Polysaccharides: Long chains of monosaccharides linked by glycosidic bonds. Examples include Cellulose (linear glucose polymer), Starch (helical energy store in plants), and Glycogen (branched energy store in animals).
Nucleic Acids: Polymers of nucleotides. Each nucleotide consists of a nitrogenous base (Adenine, Guanine, Cytosine, Thymine/Uracil), a pentose sugar (), and a phosphate group ().
Enzymes: Biological catalysts that lower the activation energy () of a reaction. They show specificity and are sensitive to temperature, , and substrate concentration .
📐Formulae
💡Examples
Problem 1:
A polypeptide chain consists of amino acids. Calculate the number of peptide bonds present and the number of water molecules () released during its synthesis.
Solution:
Number of peptide bonds = ; Number of molecules released = .
Explanation:
In a linear polymer, the number of bonds between monomers is always . Since one molecule of is eliminated for every peptide bond formed via dehydration synthesis, water molecules are released.
Problem 2:
In an enzymatic reaction, what happens to the Michaelis constant () in the presence of a competitive inhibitor?
Solution:
The increases, while remains unchanged.
Explanation:
A competitive inhibitor mimics the substrate and binds to the active site. This decreases the affinity of the enzyme for the substrate, thus increasing the (the concentration of substrate required to reach ). remains constant because high can eventually displace the inhibitor.
Problem 3:
Identify the primary difference between a Nucleoside and a Nucleotide.
Solution:
Nucleotide = Nucleoside + Phosphate group.
Explanation:
A nucleoside consists of a nitrogenous base and a sugar (). When a phosphate group is attached to the of the sugar via a phosphoester bond, it becomes a Nucleotide ().