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Trigonometry - Trigonometric Ratios of Standard Angles (0°, 30°, 45°, 60°, 90°)

Grade 9ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Trigonometric Ratios for standard angles involve calculating the values of sin\sin, cos\cos, tan\tan, csc\csc, sec\sec, and cot\cot for specific angles: 0,30,45,60,0^\circ, 30^\circ, 45^\circ, 60^\circ, and 9090^\circ. These values are constant and derived from geometric properties.

The ratios for 4545^\circ are derived from an isosceles right-angled triangle. Visualize a triangle with two equal sides of length 11 unit and a 9090^\circ angle between them; using the Pythagoras theorem, the hypotenuse becomes 2\sqrt{2} units. From this, we see sin45=12\sin 45^\circ = \frac{1}{\sqrt{2}} and cos45=12\cos 45^\circ = \frac{1}{\sqrt{2}}.

The ratios for 3030^\circ and 6060^\circ are derived from an equilateral triangle with side length 22 units. Imagine splitting this triangle into two equal halves by drawing an altitude. This creates a right-angled triangle with a base of 11, a hypotenuse of 22, and an altitude (perpendicular) of 3\sqrt{3}. For the 3030^\circ angle at the top, the side opposite is 11, and for the 6060^\circ angle at the base, the side opposite is 3\sqrt{3}.

As the angle θ\theta increases from 00^\circ to 9090^\circ, the value of sinθ\sin \theta increases from 00 to 11, while the value of cosθ\cos \theta decreases from 11 to 00. This reflects the change in the lengths of the opposite and adjacent sides relative to the hypotenuse in a unit circle.

The Tangent ratio (tanθ\tan \theta) is the quotient of Sine and Cosine (tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}). At 9090^\circ, cos90=0\cos 90^\circ = 0, making tan90\tan 90^\circ undefined or 'Not Defined' because division by zero is impossible.

Reciprocal Trigonometric Ratios are defined as: cscθ\csc \theta is the reciprocal of sinθ\sin \theta, secθ\sec \theta is the reciprocal of cosθ\cos \theta, and cotθ\cot \theta is the reciprocal of tanθ\tan \theta. For example, since sin30=12\sin 30^\circ = \frac{1}{2}, its reciprocal csc30=2\csc 30^\circ = 2.

📐Formulae

sin0=0,sin30=12,sin45=12,sin60=32,sin90=1\sin 0^\circ = 0, \sin 30^\circ = \frac{1}{2}, \sin 45^\circ = \frac{1}{\sqrt{2}}, \sin 60^\circ = \frac{\sqrt{3}}{2}, \sin 90^\circ = 1

cos0=1,cos30=32,cos45=12,cos60=12,cos90=0\cos 0^\circ = 1, \cos 30^\circ = \frac{\sqrt{3}}{2}, \cos 45^\circ = \frac{1}{\sqrt{2}}, \cos 60^\circ = \frac{1}{2}, \cos 90^\circ = 0

tan0=0,tan30=13,tan45=1,tan60=3,tan90= (Not Defined)\tan 0^\circ = 0, \tan 30^\circ = \frac{1}{\sqrt{3}}, \tan 45^\circ = 1, \tan 60^\circ = \sqrt{3}, \tan 90^\circ = \infty \text{ (Not Defined)}

cscθ=1sinθ\csc \theta = \frac{1}{\sin \theta}

secθ=1cosθ\sec \theta = \frac{1}{\cos \theta}

cotθ=1tanθ=cosθsinθ\cot \theta = \frac{1}{\tan \theta} = \frac{\cos \theta}{\sin \theta}

💡Examples

Problem 1:

Evaluate the following expression: sin60cos30+cos60sin30\sin 60^\circ \cos 30^\circ + \cos 60^\circ \sin 30^\circ

Solution:

  1. Substitute the standard values: sin60=32\sin 60^\circ = \frac{\sqrt{3}}{2} cos30=32\cos 30^\circ = \frac{\sqrt{3}}{2} cos60=12\cos 60^\circ = \frac{1}{2} sin30=12\sin 30^\circ = \frac{1}{2}
  2. Plug the values into the expression: (32×32)+(12×12)(\frac{\sqrt{3}}{2} \times \frac{\sqrt{3}}{2}) + (\frac{1}{2} \times \frac{1}{2})
  3. Calculate each term: 34+14\frac{3}{4} + \frac{1}{4}
  4. Simplify: 44=1\frac{4}{4} = 1

Explanation:

This problem uses the direct substitution of trigonometric values for 3030^\circ and 6060^\circ. The result is consistent with the identity sin(A+B)=sinAcosB+cosAsinB\sin(A+B) = \sin A \cos B + \cos A \sin B where A=60,B=30A=60, B=30.

Problem 2:

Find the value of xx if 2sin2x=32 \sin 2x = \sqrt{3} and 02x900^\circ \le 2x \le 90^\circ.

Solution:

  1. Divide both sides by 22: sin2x=32\sin 2x = \frac{\sqrt{3}}{2}
  2. Identify the standard angle for which the sine value is 32\frac{\sqrt{3}}{2}: We know that sin60=32\sin 60^\circ = \frac{\sqrt{3}}{2}
  3. Equate the angles: 2x=602x = 60^\circ
  4. Solve for xx: x=602x = \frac{60^\circ}{2} x=30x = 30^\circ

Explanation:

To find an unknown angle, isolate the trigonometric function and compare the resulting value with the standard angle table values.