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Rational and Irrational Numbers - Surds and rationalization

Grade 9ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Rational Numbers are numbers that can be expressed in the form pq\frac{p}{q}, where pp and qq are integers and q0q \neq 0. Visually, these include all integers, terminating decimals (like 0.50.5), and repeating decimals (like 0.333...0.333...) placed precisely on a number line.

Irrational Numbers are numbers that cannot be expressed as a simple fraction pq\frac{p}{q}. Their decimal expansions are non-terminating and non-recurring. On a number line, they fill the gaps between rational numbers, such as 2\sqrt{2} or π\pi. Geometrically, 2\sqrt{2} represents the diagonal of a square with side length 1.

A Surd is an irrational root of a positive rational number. For example, 3\sqrt{3} is a surd because 3 is rational but its square root is irrational. However, 4\sqrt{4} is not a surd because it simplifies to the rational number 2. Visualizing a surd x\sqrt{x} involves finding a side of a square whose area is exactly xx units.

Pure and Mixed Surds: A surd consisting entirely of an irrational number, like 50\sqrt{50}, is a pure surd. A mixed surd has a rational coefficient, like 525\sqrt{2}. You can convert a pure surd to mixed by factoring out the largest perfect square (e.g., 50=25×2=52\sqrt{50} = \sqrt{25 \times 2} = 5\sqrt{2}).

Like and Unlike Surds: Like surds have the same irrational factor (e.g., 373\sqrt{7} and 272\sqrt{7}). Only like surds can be added or subtracted, similar to how like terms 3x3x and 2x2x are combined in algebra. Unlike surds, such as 2\sqrt{2} and 3\sqrt{3}, cannot be combined into a single radical term.

Rationalization is the process of eliminating a radical from the denominator of a fraction. If the denominator is a monomial surd like a\sqrt{a}, we multiply both numerator and denominator by a\sqrt{a}. If the denominator is a binomial like a+ba + \sqrt{b}, we multiply by its conjugate aba - \sqrt{b}.

The Conjugate of a binomial surd a+ba + \sqrt{b} is aba - \sqrt{b}. When these two are multiplied, the result is always a rational number (a2ba^2 - b). This property is the foundation for rationalizing denominators containing two terms.

Geometric Representation: Irrational numbers like x\sqrt{x} can be represented on a number line using the Pythagorean theorem. To represent 2\sqrt{2}, construct a right-angled triangle with base and height of 1 unit. The hypotenuse will be 2\sqrt{2}, which can then be projected onto the number line using a compass arc.

📐Formulae

ab=a×b\sqrt{ab} = \sqrt{a} \times \sqrt{b}

ab=ab\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}

(a+b)(ab)=ab(\sqrt{a} + \sqrt{b})(\sqrt{a} - \sqrt{b}) = a - b

(a+b)(ab)=a2b(a + \sqrt{b})(a - \sqrt{b}) = a^2 - b

(a+b)2=a+b+2ab(\sqrt{a} + \sqrt{b})^2 = a + b + 2\sqrt{ab}

(ab)2=a+b2ab(\sqrt{a} - \sqrt{b})^2 = a + b - 2\sqrt{ab}

Rationalizing factor for 1a±b\frac{1}{\sqrt{a} \pm \sqrt{b}} is ab\sqrt{a} \mp \sqrt{b}

💡Examples

Problem 1:

Rationalize the denominator of 473\frac{4}{\sqrt{7} - \sqrt{3}}

Solution:

Step 1: Identify the conjugate of the denominator 73\sqrt{7} - \sqrt{3}, which is 7+3\sqrt{7} + \sqrt{3}. Step 2: Multiply both the numerator and the denominator by the conjugate: 473×7+37+3\frac{4}{\sqrt{7} - \sqrt{3}} \times \frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} + \sqrt{3}} Step 3: Simplify the numerator: 4(7+3)4(\sqrt{7} + \sqrt{3}) Step 4: Simplify the denominator using (ab)(a+b)=a2b2(a-b)(a+b) = a^2 - b^2: (7)2(3)2=73=4(\sqrt{7})^2 - (\sqrt{3})^2 = 7 - 3 = 4 Step 5: Combine and simplify: 4(7+3)4=7+3\frac{4(\sqrt{7} + \sqrt{3})}{4} = \sqrt{7} + \sqrt{3}

Explanation:

To rationalize a binomial denominator, we multiply by its conjugate to create a difference of squares, which effectively removes the square roots from the denominator.

Problem 2:

Simplify: 320+451253\sqrt{20} + \sqrt{45} - \sqrt{125}

Solution:

Step 1: Express each surd in its simplest mixed form by finding perfect square factors. 20=4×5=25\sqrt{20} = \sqrt{4 \times 5} = 2\sqrt{5} 45=9×5=35\sqrt{45} = \sqrt{9 \times 5} = 3\sqrt{5} 125=25×5=55\sqrt{125} = \sqrt{25 \times 5} = 5\sqrt{5} Step 2: Substitute these values back into the expression: 3(25)+35553(2\sqrt{5}) + 3\sqrt{5} - 5\sqrt{5} Step 3: Perform the multiplication: 65+35556\sqrt{5} + 3\sqrt{5} - 5\sqrt{5} Step 4: Combine the like surds: (6+35)5=45(6 + 3 - 5)\sqrt{5} = 4\sqrt{5}

Explanation:

Addition and subtraction of surds are only possible when they are 'like surds'. By simplifying each radical to its simplest mixed form, we can identify and combine the common 5\sqrt{5} terms.