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Rational and Irrational Numbers - Representation on the number line

Grade 9ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Rational Numbers are numbers expressed in the form pq\frac{p}{q}, where pp and qq are integers and q0q \neq 0. On a number line, a rational number like 35\frac{3}{5} is represented by dividing the unit length between 00 and 11 into 55 equal segments and selecting the 3rd3^{rd} division point from the origin.

Irrational Numbers are real numbers that cannot be expressed as a simple fraction pq\frac{p}{q}. Their decimal expansions are non-terminating and non-recurring (e.g., 21.414...\sqrt{2} \approx 1.414... or π3.1415...\pi \approx 3.1415...). Visually, these points fill the 'gaps' left by rational numbers on the number line.

The Pythagoras Theorem (h2=b2+p2h^2 = b^2 + p^2) is the fundamental tool for representing square roots of non-perfect squares on the number line. For example, to represent 2\sqrt{2}, we visualize a right-angled triangle with a base of 11 unit and a height of 11 unit; the hypotenuse length will be exactly 2\sqrt{2}.

To represent n\sqrt{n} on a number line (where nn is a positive integer), we first locate n1\sqrt{n-1}. By constructing a perpendicular line segment of unit length (11) at the point n1\sqrt{n-1}, the distance from the origin to the top of this perpendicular becomes n\sqrt{n} units. This creates a 'Square Root Spiral' effect when repeated.

Geometric Construction of x\sqrt{x} for any positive real number xx: Draw a line segment AB=xAB = x units and extend it to CC such that BC=1BC = 1 unit. Find the midpoint OO of ACAC and draw a semi-circle with radius OAOA. A perpendicular line drawn from BB to the semi-circle at point DD will have a length BD=xBD = \sqrt{x}. This length can then be marked on the number line using a compass.

Successive Magnification is a visual method to represent terminating or non-terminating recurring decimals. It involves looking through a 'magnifying glass' at the number line. To find 2.6652.665, we first look between 22 and 33, then zoom into the interval 2.62.6 and 2.72.7, and further zoom into 2.662.66 and 2.672.67 until 33 decimal places are reached.

The Real Number Line Property states that every point on the number line represents a unique real number (either rational or irrational), and conversely, every real number can be represented by a unique point on the line. This establishes a one-to-one correspondence between real numbers and points on a geometric line.

📐Formulae

Definition of Rational Number: Q={pq:p,qZ,q0}Q = \{ \frac{p}{q} : p, q \in \mathbb{Z}, q \neq 0 \}

Pythagoras Theorem for construction: Hypotenuse=(Base)2+(Perpendicular)2\text{Hypotenuse} = \sqrt{(\text{Base})^2 + (\text{Perpendicular})^2}

Hypotenuse for 2\sqrt{2}: h=12+12=2h = \sqrt{1^2 + 1^2} = \sqrt{2}

Hypotenuse for 3\sqrt{3}: h=(2)2+12=3h = \sqrt{(\sqrt{2})^2 + 1^2} = \sqrt{3}

Formula to find a rational number between aa and bb: a+b2\frac{a + b}{2}

Formula to find an irrational number between two positive rational numbers aa and bb: a×b\sqrt{a \times b} (provided abab is not a perfect square)

💡Examples

Problem 1:

Represent 5\sqrt{5} on the number line using geometric construction.

Solution:

Step 1: On the number line, take a distance OA=2OA = 2 units from the origin OO. Step 2: Draw a perpendicular AB=1AB = 1 unit at point AA. Step 3: Join OBOB. By Pythagoras Theorem, OB2=OA2+AB2=22+12=4+1=5OB^2 = OA^2 + AB^2 = 2^2 + 1^2 = 4 + 1 = 5. Therefore, OB=5OB = \sqrt{5}. Step 4: Using OO as the center and OBOB as the radius, draw an arc that intersects the number line at point PP. Step 5: The point PP represents 5\sqrt{5} on the number line.

Explanation:

The problem uses the Pythagoras theorem to create a length of 5\sqrt{5} by choosing a base of 22 and a height of 11, which are easy to mark on a standard grid.

Problem 2:

Find one rational and one irrational number between 33 and 44.

Solution:

  1. For the rational number: Use the mean formula a+b2\frac{a+b}{2}. Rational number =3+42=72=3.5= \frac{3 + 4}{2} = \frac{7}{2} = 3.5.
  2. For the irrational number: Use the square root of the product ab\sqrt{ab}. Irrational number =3×4=12=23= \sqrt{3 \times 4} = \sqrt{12} = 2\sqrt{3}. Alternatively, we can write a non-terminating non-repeating decimal like 3.1010010001...3.1010010001...

Explanation:

A rational number can always be found by the average of two numbers. An irrational number can be found by taking the square root of the product of two numbers, provided the result is not a perfect square.