krit.club logo

Geometry - Pythagoras Theorem and its Converse

Grade 9ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Right-Angled Triangle: A triangle in which one angle is exactly 9090^\circ. Visually, this is often indicated by a small square symbol at the vertex where the two perpendicular sides (the base and the height) meet. The side opposite to this 9090^\circ angle is the longest side, known as the hypotenuse.

The Pythagoras Theorem: In any right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. If the sides are aa and bb and the hypotenuse is cc, then c2=a2+b2c^2 = a^2 + b^2. Visually, if you draw a square on each side of the triangle, the area of the largest square is equal to the combined area of the two smaller squares.

Converse of Pythagoras Theorem: If the square of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle must be a right-angled triangle. The angle opposite the longest side will be the 9090^\circ angle.

Pythagorean Triplets: A set of three positive integers (a,b,c)(a, b, c) that satisfy the condition a2+b2=c2a^2 + b^2 = c^2. Common examples include (3,4,5)(3, 4, 5), (5,12,13)(5, 12, 13), and (8,15,17)(8, 15, 17). Any multiple of a Pythagorean triplet, such as (6,8,10)(6, 8, 10), is also a Pythagorean triplet.

Diagonal of a Rectangle and Square: In a rectangle with length ll and breadth bb, the diagonal dd creates two right-angled triangles, where d=l2+b2d = \sqrt{l^2 + b^2}. In a square with side ss, the diagonal dd forms a right-angled triangle where the legs are equal, resulting in d=s2d = s\sqrt{2}.

Identifying Triangle Types: Using the side lengths a,b,a, b, and cc (where cc is the longest side), we can classify triangles: if c2=a2+b2c^2 = a^2 + b^2, it is right-angled; if c2>a2+b2c^2 > a^2 + b^2, the triangle is obtuse-angled (one angle >90> 90^\circ); if c2<a2+b2c^2 < a^2 + b^2, the triangle is acute-angled (all angles <90< 90^\circ).

📐Formulae

Pythagoras Theorem: h2=p2+b2h^2 = p^2 + b^2

Length of Hypotenuse: h=p2+b2h = \sqrt{p^2 + b^2}

Length of Perpendicular: p=h2b2p = \sqrt{h^2 - b^2}

Length of Base: b=h2p2b = \sqrt{h^2 - p^2}

Diagonal of a Rectangle: d=l2+w2d = \sqrt{l^2 + w^2}

Diagonal of a Square: d=a2d = a\sqrt{2}

Condition for Pythagorean Triplet: c2=a2+b2c^2 = a^2 + b^2

💡Examples

Problem 1:

A ladder 1313 m long reaches a window 1212 m above the ground. Find the distance of the foot of the ladder from the wall.

Solution:

Let the length of the ladder be the hypotenuse h=13h = 13 m. Let the height of the window be the perpendicular p=12p = 12 m. We need to find the base bb. \n Using Pythagoras Theorem: \n b2=h2p2b^2 = h^2 - p^2 \n b2=132122b^2 = 13^2 - 12^2 \n b2=169144b^2 = 169 - 144 \n b2=25b^2 = 25 \n b=25=5b = \sqrt{25} = 5 m.

Explanation:

In this real-world scenario, the wall, the ground, and the ladder form a right-angled triangle. The ladder represents the hypotenuse because it is leaning opposite the 9090^\circ angle formed by the wall and the ground.

Problem 2:

Determine whether a triangle with sides 88 cm, 1515 cm, and 1717 cm is a right-angled triangle.

Solution:

Let the sides be a=8a = 8, b=15b = 15, and the longest side c=17c = 17. \n Calculate the sum of squares of the smaller sides: \n a2+b2=82+152=64+225=289a^2 + b^2 = 8^2 + 15^2 = 64 + 225 = 289 \n Calculate the square of the longest side: \n c2=172=289c^2 = 17^2 = 289 \n Since a2+b2=c2a^2 + b^2 = c^2 (289=289289 = 289)...

Explanation:

According to the Converse of Pythagoras Theorem, if the square of the longest side equals the sum of the squares of the other two sides, the triangle is right-angled. Since the values satisfy the equation, this is a right-angled triangle.