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Number - Ratio, proportion, and rates of change

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Ratios are used to compare quantities of the same kind, expressed in the form a:ba:b or a:b:ca:b:c. To simplify a ratio, divide all parts by their highest common factor. Visually, a ratio like 2:32:3 can be seen as a bar split into 55 equal segments, where 22 segments are one color and 33 are another.

Proportional division involves sharing a total amount into parts defined by a ratio. To calculate this, sum the parts of the ratio to find the 'total parts', divide the total quantity by this sum to find the value of 'one part', and then multiply each ratio number by that value. A pie chart is a helpful visual where the size of each slice corresponds to its ratio share.

Direct proportion occurs when two quantities increase or decrease at the same rate, represented by the equation y=kxy = kx, where kk is the constant of proportionality. On a graph, direct proportion always appears as a straight line starting from the origin (0,0)(0,0) and extending upwards at a constant gradient.

Inverse proportion describes a relationship where as one variable increases, the other decreases such that their product remains constant, represented as y=kxy = \frac{k}{x} or xy=kxy = k. The visual representation of this is a reciprocal curve (hyperbola) that gets closer to the xx and yy axes but never touches them.

Unit rates and compound units relate different types of measures, such as speed (distance/time), density (mass/volume), or pressure (force/area). These are often visualized using formula triangles, with the 'total' quantity at the top and the two rates/components at the bottom corners.

Percentage change is a way to express the difference between a new value and an old value as a percentage of the original. If you visualize the original amount as a 100%100\% bar, an increase is an additional segment added to the end, while a decrease is a portion removed from the original bar length.

Map scales and model scales use ratios (e.g., 1:n1:n) to represent real-world dimensions. In a 1:1001:100 scale, 1cm1 cm on a drawing represents 100cm100 cm in reality. This concept can be visualized by zooming into a shape; while the side lengths change according to the ratio, the shape's angles and proportions remain identical (similarity).

📐Formulae

Ratio=a:bRatio = a:b

y=kxy = kx (Direct Proportion)

y=kxy = \frac{k}{x} (Inverse Proportion)

Speed=DistanceTimeSpeed = \frac{Distance}{Time}

Density=MassVolumeDensity = \frac{Mass}{Volume}

Percentage Change=NewOriginalOriginal×100%Percentage \ Change = \frac{\text{New} - \text{Original}}{\text{Original}} \times 100\%

Multiplier=1±Percentage100\text{Multiplier} = 1 \pm \frac{\text{Percentage}}{100}

New Value=Original Value×Multiplier\text{New Value} = \text{Original Value} \times \text{Multiplier}

💡Examples

Problem 1:

A juice recipe uses orange juice and sparkling water in the ratio 3:53:5. If you want to make 400ml400 ml of the drink, how much of each ingredient is needed?

Solution:

Step 1: Find the total number of parts in the ratio: 3+5=83 + 5 = 8 parts. \ Step 2: Calculate the volume of one part: 4008=50ml\frac{400}{8} = 50 ml. \ Step 3: Multiply the orange juice ratio by the part value: 3×50=150ml3 \times 50 = 150 ml. \ Step 4: Multiply the water ratio by the part value: 5×50=250ml5 \times 50 = 250 ml. \ Final Answer: 150ml150 ml orange juice and 250ml250 ml water.

Explanation:

This problem uses the method of proportional division. By finding the value of a single 'unit' or 'part', we can scale the ratio up to match the total volume required.

Problem 2:

The variable yy is inversely proportional to xx. When x=10x = 10, y=4y = 4. Find the value of yy when x=5x = 5.

Solution:

Step 1: Write the formula for inverse proportion: y=kxy = \frac{k}{x}. \ Step 2: Substitute the known values to find kk: 4=k10    k=4×10=404 = \frac{k}{10} \implies k = 4 \times 10 = 40. \ Step 3: Write the complete equation: y=40xy = \frac{40}{x}. \ Step 4: Substitute x=5x = 5 into the equation to find yy: y=405=8y = \frac{40}{5} = 8. \ Final Answer: y=8y = 8.

Explanation:

In an inverse proportion, the product of xx and yy must always equal the constant kk. Since 10×4=4010 \times 4 = 40, the new xx and yy must also multiply to 4040, so 5×8=405 \times 8 = 40.