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Geometry and Trigonometry - Pythagorean theorem and its applications

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Right-Angled Triangle: The Pythagorean theorem exclusively applies to right-angled triangles, which are triangles containing one 9090^{\circ} angle. The side opposite this right angle is called the hypotenuse, and it is always the longest side of the triangle. Visually, if you look at a right triangle, the hypotenuse is the diagonal side that does not touch the square symbol representing the 9090^{\circ} angle.

The Fundamental Theorem: The theorem states that in any right-angled triangle, the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares whose sides are the two legs (the shorter sides). This is represented by the equation a2+b2=c2a^2 + b^2 = c^2, where cc is the hypotenuse.

Geometric Visualization: Imagine a right triangle where a physical square is drawn outwards from each of the three sides. If the sides are 33, 44, and 55, the areas of the squares on the legs are 99 (3×33 \times 3) and 1616 (4×44 \times 4). The area of the square on the hypotenuse is 2525 (5×55 \times 5). Note that 9+16=259 + 16 = 25, visually confirming the theorem.

Finding the Hypotenuse: To find the length of the hypotenuse (cc) when the lengths of the legs (aa and bb) are known, you must sum the squares of the legs and then take the square root of the result: c=a2+b2c = \sqrt{a^2 + b^2}.

Finding a Shorter Side: To find a missing leg (aa or bb) when the hypotenuse (cc) and one leg are known, subtract the square of the known leg from the square of the hypotenuse and then take the square root: a=c2b2a = \sqrt{c^2 - b^2}.

The Converse of Pythagoras: This concept is used to verify if a triangle is right-angled. If the side lengths of a triangle satisfy the equation a2+b2=c2a^2 + b^2 = c^2, then the triangle must have a 9090^{\circ} angle opposite the longest side. If the equation does not balance, the triangle is not right-angled.

Pythagorean Triples: These are sets of three positive integers (a,b,c)(a, b, c) that perfectly satisfy the theorem. Common examples include (3,4,5)(3, 4, 5), (5,12,13)(5, 12, 13), and (8,15,17)(8, 15, 17). Multiples of these sets (e.g., 6,8,106, 8, 10) are also triples.

3D Applications: The theorem can be applied to find the space diagonal of a cuboid. Visually, this is a line connecting one bottom corner to the opposite top corner. It involves two steps: first finding the diagonal of the base using dbase=l2+w2d_{base} = \sqrt{l^2 + w^2}, then using that to find the space diagonal: D=dbase2+h2D = \sqrt{d_{base}^2 + h^2}, which simplifies to D=l2+w2+h2D = \sqrt{l^2 + w^2 + h^2}.

📐Formulae

a2+b2=c2a^2 + b^2 = c^2

c=a2+b2c = \sqrt{a^2 + b^2}

a=c2b2a = \sqrt{c^2 - b^2}

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

D=l2+w2+h2D = \sqrt{l^2 + w^2 + h^2}

💡Examples

Problem 1:

A 13m long ladder is leaning against a vertical wall. The base of the ladder is 5m away from the wall on horizontal ground. How high up the wall does the ladder reach?

Solution:

Step 1: Identify the parts of the triangle. The ladder is the hypotenuse (c=13c = 13), and the distance from the wall is one leg (b=5b = 5). We need to find the height (aa). Step 2: Use the rearranged formula a=c2b2a = \sqrt{c^2 - b^2}. Step 3: Substitute the values: a=13252a = \sqrt{13^2 - 5^2}. Step 4: Calculate the squares: a=16925a = \sqrt{169 - 25}. Step 5: Subtract: a=144a = \sqrt{144}. Step 6: Solve the square root: a=12a = 12.

Explanation:

In this real-world application, the wall and the ground form a 9090^{\circ} angle. Since we are looking for one of the shorter sides (the height), we subtract the square of the known side from the square of the hypotenuse.

Problem 2:

Determine if a triangle with side lengths 7cm, 24cm, and 25cm is a right-angled triangle.

Solution:

Step 1: Identify the longest side as the potential hypotenuse (c=25c = 25) and the other two as legs (a=7,b=24a = 7, b = 24). Step 2: Calculate a2+b2a^2 + b^2: 72+242=49+576=6257^2 + 24^2 = 49 + 576 = 625. Step 3: Calculate c2c^2: 252=62525^2 = 625. Step 4: Compare the results: Since a2+b2=c2a^2 + b^2 = c^2 (625=625625 = 625), the condition is met.

Explanation:

This uses the Converse of the Pythagorean theorem. Because the square of the longest side equals the sum of the squares of the other two sides, the triangle must be right-angled.