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Triangles - Inequalities in a Triangle

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Angle-Side Relationship (Longer Side): If two sides of a triangle are unequal, the angle opposite to the longer side is greater. For example, in a triangle where side ACAC is clearly longer than side ABAB, the angle facing ACAC (which is B\angle B) will be larger than the angle facing ABAB (which is C\angle C).

Side-Angle Relationship (Greater Angle): In any triangle, the side opposite to the larger angle is longer. Visually, if you widen the opening of an angle in a triangle, the side connecting the two rays of that angle must grow longer to close the triangle.

The Triangle Inequality Theorem: The sum of any two sides of a triangle is always greater than the third side. If you have three segments of lengths aa, bb, and cc, they can only form a closed triangle if a+b>ca + b > c, b+c>ab + c > a, and a+c>ba + c > b. If the sum of two sides were equal to the third, the 'triangle' would collapse into a straight line.

The Difference Property: The difference between any two sides of a triangle is always less than the third side. Mathematically, for sides aa, bb, and cc, ab<c|a - b| < c. This ensures that the two sides are long enough to actually meet when connected to the third side.

Perpendicular Distance: From a point not on a given line, the perpendicular line segment drawn to the line is the shortest of all line segments that can be drawn. This is because any other segment forms a right-angled triangle where the perpendicular is one side and the other segment is the hypotenuse; since the hypotenuse is opposite the 9090^\circ angle (the largest angle), it must be the longest side.

Side Length Range: For any triangle with known sides aa and bb, the length of the third side xx must fall within the range ab<x<a+b|a - b| < x < a + b. Visually, this represents the third side being longer than the 'gap' between the two known sides but shorter than the two sides laid out in a straight line.

📐Formulae

In ΔABC,AB+BC>AC\text{In } \Delta ABC, AB + BC > AC

In ΔABC,BC+AC>AB\text{In } \Delta ABC, BC + AC > AB

In ΔABC,AB+AC>BC\text{In } \Delta ABC, AB + AC > BC

|AB - BC| < AC

If A>B>C, then BC>AC>AB\text{If } \angle A > \angle B > \angle C, \text{ then } BC > AC > AB

💡Examples

Problem 1:

Is it possible to construct a triangle with sides of lengths 5 cm5\text{ cm}, 8 cm8\text{ cm}, and 15 cm15\text{ cm}?

Solution:

  1. According to the Triangle Inequality Theorem, the sum of any two sides must be greater than the third side.
  2. Let a=5a = 5, b=8b = 8, and c=15c = 15.
  3. Check the sum of the two smaller sides: a+b=5+8=13a + b = 5 + 8 = 13.
  4. Compare this sum to the third side: 13<1513 < 15.
  5. Since the sum of two sides is not greater than the third side (131513 \ngtr 15), a triangle cannot be formed.

Explanation:

To check if a triangle exists, you only need to verify if the sum of the two shortest sides is strictly greater than the longest side.

Problem 2:

In ΔPQR\Delta PQR, if P=45\angle P = 45^\circ and Q=65\angle Q = 65^\circ, determine which side of the triangle is the longest and which is the shortest.

Solution:

  1. First, find the third angle using the Angle Sum Property: R=180(P+Q)=180(45+65)=180110=70\angle R = 180^\circ - (\angle P + \angle Q) = 180^\circ - (45^\circ + 65^\circ) = 180^\circ - 110^\circ = 70^\circ.
  2. Compare the angle measures: 45<65<7045^\circ < 65^\circ < 70^\circ, so P<Q<R\angle P < \angle Q < \angle R.
  3. Use the property that the side opposite the larger angle is longer:
    • Side opposite to R\angle R (7070^\circ) is PQPQ.
    • Side opposite to Q\angle Q (6565^\circ) is PRPR.
    • Side opposite to P\angle P (4545^\circ) is QRQR.
  4. Therefore, QR<PR<PQQR < PR < PQ. The longest side is PQPQ and the shortest side is QRQR.

Explanation:

The relative lengths of the sides of a triangle are determined by the measures of the angles opposite to them. Larger angles face longer sides.