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Surface Areas and Volumes - Surface Area of a Sphere and Hemisphere

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A sphere is a three-dimensional solid where every point on its surface is at a constant distance, known as the radius (rr), from a fixed point called the center. Visually, it resembles a perfectly symmetrical round ball, like a marble or a planet.

The surface area of a sphere is the total area covered by its exterior boundary. An interesting visual way to understand this is that the surface area of a sphere is exactly equal to the area of four circles having the same radius (rr).

A hemisphere is formed when a sphere is divided into two equal halves by a plane passing through its center. Visually, it looks like a bowl or a dome with a flat circular base and a curved top.

The Curved Surface Area (CSA) of a hemisphere refers only to the area of the rounded, outer part. Since a hemisphere is half of a sphere, its CSA is exactly half of the sphere's total surface area.

The Total Surface Area (TSA) of a solid hemisphere includes both the curved surface and the flat circular base. To visualize this, think of a solid wooden bowl; the TSA would include the outer rounded wood and the flat circular rim/top.

The surface area of these shapes depends solely on the radius (rr). Because the formula involves r2r^2, if you double the radius of a sphere, its surface area increases by a factor of four (22=42^2 = 4).

Surface area is always measured in square units, such as cm2cm^2 or m2m^2. When solving problems, ensure that the radius and the resulting area use consistent units.

📐Formulae

SurfaceAreaofaSphere=4πr2Surface Area of a Sphere = 4 \pi r^2

CurvedSurfaceArea(CSA)ofaHemisphere=2πr2Curved Surface Area (CSA) of a Hemisphere = 2 \pi r^2

TotalSurfaceArea(TSA)ofaHemisphere=3πr2Total Surface Area (TSA) of a Hemisphere = 3 \pi r^2

AreaofthecircularbaseofaHemisphere=πr2Area of the circular base of a Hemisphere = \pi r^2

Radius(r)=Diameter(d)2Radius (r) = \frac{Diameter (d)}{2}

💡Examples

Problem 1:

Find the surface area of a sphere of radius 7cm7 cm. (Use π=227\pi = \frac{22}{7})

Solution:

  1. Given: Radius (rr) = 7cm7 cm.
  2. Formula for Surface Area of a Sphere = 4πr24 \pi r^2.
  3. Substitute the values: SA=4×227×(7)2SA = 4 \times \frac{22}{7} \times (7)^2.
  4. SA=4×227×7×7SA = 4 \times \frac{22}{7} \times 7 \times 7.
  5. SA=4×22×7=616cm2SA = 4 \times 22 \times 7 = 616 cm^2.

Explanation:

To find the surface area of a sphere, identify the radius and substitute it into the formula 4πr24 \pi r^2. Since the radius is a multiple of 7, using π=227\pi = \frac{22}{7} makes the calculation simpler by allowing for cancellation.

Problem 2:

Find the Total Surface Area (TSA) of a hemisphere of radius 10cm10 cm. (Use π=3.14\pi = 3.14)

Solution:

  1. Given: Radius (rr) = 10cm10 cm.
  2. Formula for TSA of a Hemisphere = 3πr23 \pi r^2.
  3. Substitute the values: TSA=3×3.14×(10)2TSA = 3 \times 3.14 \times (10)^2.
  4. TSA=3×3.14×100TSA = 3 \times 3.14 \times 100.
  5. TSA=3×314=942cm2TSA = 3 \times 314 = 942 cm^2.

Explanation:

For a solid hemisphere, we must account for both the curved surface (2πr22 \pi r^2) and the flat circular base (πr2\pi r^2), which totals 3πr23 \pi r^2. Using 3.143.14 for π\pi is convenient here because the radius squared (100100) easily clears the decimals.