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Surface Areas and Volumes - Surface Area of a Right Circular Cone

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A Right Circular Cone is a three-dimensional geometric shape generated by revolving a right-angled triangle about one of its sides. Visually, it consists of a flat circular base and a curved surface that tapers to a single point called the vertex, which is located directly above the center of the circular base.

The cone is defined by three primary dimensions: the radius (rr) of the circular base, the vertical height (hh) which is the perpendicular distance from the vertex to the center of the base, and the slant height (ll) which is the distance from the vertex to any point on the edge of the circular base.

The relationship between rr, hh, and ll is derived from the Pythagorean theorem because they form a right-angled triangle within the cone. This relationship is expressed as l2=r2+h2l^2 = r^2 + h^2. Visually, if you slice the cone vertically from the vertex to the center of the base, the cross-section is a right triangle with legs rr and hh, and hypotenuse ll.

The Curved Surface Area (CSA), also known as Lateral Surface Area, represents the area of the side surface excluding the base. Visually, if the curved surface were cut along the slant height and flattened, it would form a sector of a circle with a radius equal to the slant height ll and an arc length equal to the circumference of the cone's base (2πr2\pi r).

The Total Surface Area (TSA) is the sum of the curved surface area and the area of the circular base. Visually, this includes the entire exterior of the cone, like a party hat with a circular lid attached to the bottom.

Surface area is always measured in square units, such as cm2cm^2 or m2m^2. For calculations, the value of π\pi is generally taken as 227\frac{22}{7} or 3.143.14 unless specified otherwise.

📐Formulae

Slant Height: l=r2+h2l = \sqrt{r^2 + h^2}

Curved Surface Area (CSA): CSA=πrlCSA = \pi r l

Area of the Base: BaseArea=πr2Base Area = \pi r^2

Total Surface Area (TSA): TSA=πrl+πr2TSA = \pi r l + \pi r^2

Simplified Total Surface Area: TSA=πr(l+r)TSA = \pi r(l + r)

💡Examples

Problem 1:

Find the curved surface area of a right circular cone whose slant height is 10 cm10\text{ cm} and base radius is 7 cm7\text{ cm}. (Use π=227\pi = \frac{22}{7})

Solution:

Given:

  • Radius of the base (rr) = 7 cm7\text{ cm}
  • Slant height (ll) = 10 cm10\text{ cm}

Using the formula for Curved Surface Area: CSA=πrlCSA = \pi r l CSA=227×7×10CSA = \frac{22}{7} \times 7 \times 10 CSA=22×10CSA = 22 \times 10 CSA=220 cm2CSA = 220\text{ cm}^2

Therefore, the curved surface area of the cone is 220 cm2220\text{ cm}^2.

Explanation:

To find the curved surface area, we directly apply the formula πrl\pi r l since both the radius and the slant height are provided in the problem.

Problem 2:

The height of a cone is 16 cm16\text{ cm} and its base radius is 12 cm12\text{ cm}. Find the total surface area of the cone. (Use π=3.14\pi = 3.14)

Solution:

Given:

  • Radius (rr) = 12 cm12\text{ cm}
  • Height (hh) = 16 cm16\text{ cm}

Step 1: Find the slant height (ll) l=r2+h2l = \sqrt{r^2 + h^2} l=122+162l = \sqrt{12^2 + 16^2} l=144+256l = \sqrt{144 + 256} l=400=20 cml = \sqrt{400} = 20\text{ cm}

Step 2: Find the Total Surface Area (TSA) TSA=πr(l+r)TSA = \pi r(l + r) TSA=3.14×12×(20+12)TSA = 3.14 \times 12 \times (20 + 12) TSA=3.14×12×32TSA = 3.14 \times 12 \times 32 TSA=3.14×384TSA = 3.14 \times 384 TSA=1205.76 cm2TSA = 1205.76\text{ cm}^2

Therefore, the total surface area of the cone is 1205.76 cm21205.76\text{ cm}^2.

Explanation:

Since the slant height was not given, we first used the Pythagorean relationship l=r2+h2l = \sqrt{r^2 + h^2} to calculate it. Then, we substituted the values of rr and ll into the TSA formula.