krit.club logo

Polynomials - Zeroes of a Polynomial

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A zero of a polynomial p(x)p(x) is a real number cc such that p(c)=0p(c) = 0. Visually, if we think of the polynomial as a machine where we drop in a value xx, the 'zeroes' are the specific inputs that result in an output of exactly 00.

A non-zero constant polynomial, such as p(x)=5p(x) = 5, has no zeroes because the value remains constant and never reaches zero. Visually, this can be imagined as a horizontal line that never touches or crosses the xx-axis.

The zero polynomial, denoted by p(x)=0p(x) = 0, is unique because every real number is considered a zero for it. In a graphical sense, the zero polynomial lies exactly on the xx-axis at all points.

Every linear polynomial in one variable has one and only one zero. For a linear equation ax+b=0ax + b = 0, the zero represents the unique point where the straight line graph of the polynomial intersects the xx-axis.

A polynomial can have more than one zero, but the total number of zeroes cannot exceed its degree. For example, a quadratic polynomial of degree 22 can be visualized as a U-shaped curve (parabola) that can cross the xx-axis at most at two distinct points.

It is important to note that a zero of a polynomial does not have to be the number 00. A polynomial like p(x)=x1p(x) = x - 1 has a zero at 11. Conversely, 00 can be a zero of a polynomial, as seen in p(x)=x2p(x) = x^2, where the graph touches the origin (0,0)(0,0).

To find the zero of any polynomial p(x)p(x), we solve the polynomial equation p(x)=0p(x) = 0. This algebraic process is the method used to identify the 'roots' of the equation, which are identical to the 'zeroes' of the polynomial.

📐Formulae

General form of a linear polynomial: p(x)=ax+b,a0p(x) = ax + b, a \neq 0

Zero of a linear polynomial: x=bax = -\frac{b}{a}

Condition for cc to be a zero of p(x)p(x): p(c)=0p(c) = 0

Polynomial Equation: p(x)=0p(x) = 0

💡Examples

Problem 1:

Find the zero of the polynomial p(x)=3x+2p(x) = 3x + 2.

Solution:

Step 1: To find the zero, set the polynomial equal to zero: p(x)=0p(x) = 0. Step 2: Substitute the expression: 3x+2=03x + 2 = 0. Step 3: Transpose the constant 22 to the right side: 3x=23x = -2. Step 4: Divide by the coefficient of xx: x=23x = -\frac{2}{3}.

Explanation:

We solve the linear equation by isolating xx. The value x=23x = -\frac{2}{3} is the unique zero of the given linear polynomial.

Problem 2:

Verify whether x=2x = 2 and x=2x = -2 are zeroes of the polynomial p(x)=x24p(x) = x^2 - 4.

Solution:

Step 1: Check for x=2x = 2 by calculating p(2)p(2). p(2)=(2)24=44=0p(2) = (2)^2 - 4 = 4 - 4 = 0 Step 2: Check for x=2x = -2 by calculating p(2)p(-2). p(2)=(2)24=44=0p(-2) = (-2)^2 - 4 = 4 - 4 = 0

Explanation:

Since p(2)=0p(2) = 0 and p(2)=0p(-2) = 0, both 22 and 2-2 are zeroes of the polynomial x24x^2 - 4. This is a quadratic polynomial, and it has two distinct real zeroes.