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Number Systems - Introduction to Number Systems

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Natural Numbers and Whole Numbers: Natural numbers (NN) are counting numbers starting from 11 (1,2,3,…1, 2, 3, \dots). Whole numbers (WW) include zero along with all natural numbers (0,1,2,3,…0, 1, 2, 3, \dots). On a number line, these are visualized as discrete points starting from 00 or 11 and extending infinitely to the right.

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Integers: Integers (ZZ) comprise all whole numbers and their negative counterparts (…,βˆ’3,βˆ’2,βˆ’1,0,1,2,3,…\dots, -3, -2, -1, 0, 1, 2, 3, \dots). Visually, the number line extends in both directions from the origin (00), with positive integers to the right and negative integers to the left.

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Rational Numbers: A number is rational if it can be written in the form pq\frac{p}{q}, where pp and qq are integers and q≠0q \neq 0. This set includes integers, terminating decimals (like 0.5=120.5 = \frac{1}{2}), and non-terminating repeating decimals (like 0.333⋯=130.333\dots = \frac{1}{3}). On a number line, rational numbers are densely packed between any two integers.

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Irrational Numbers: These are numbers that cannot be expressed in the form pq\frac{p}{q}. Their decimal expansions are non-terminating and non-repeating. Examples include 2\sqrt{2}, 3\sqrt{3}, and Ο€\pi. Visually, they occupy specific positions on the number line that 'fill the gaps' left by rational numbers.

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Real Numbers: The collection of all rational and irrational numbers together forms the set of Real numbers (RR). Every real number is represented by a unique point on the number line, and every point on the number line represents a unique real number. This continuous line is often called the Real Number Line.

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Decimal Expansion Characteristics: Rational numbers have decimal expansions that either terminate (e.g., 78=0.875\frac{7}{8} = 0.875) or are non-terminating repeating (e.g., 103=3.333…\frac{10}{3} = 3.333\dots). Irrational numbers always have non-terminating, non-repeating decimal expansions (e.g., 2=1.4142135…\sqrt{2} = 1.4142135\dots).

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Density Property: Between any two given rational numbers, there are infinitely many rational numbers. This can be visualized by repeatedly zooming into any segment of the number line; no matter how small the interval, more numbers can always be found using the average method or the common denominator method.

πŸ“Formulae

Rational Number Form: r=pq,Β whereΒ p,q∈ZΒ andΒ qβ‰ 0r = \frac{p}{q}, \text{ where } p, q \in Z \text{ and } q \neq 0

Finding nn rational numbers between xx and yy: Calculate d=yβˆ’xn+1d = \frac{y - x}{n + 1}. The numbers are x+d,x+2d,x+3d,…,x+ndx+d, x+2d, x+3d, \dots, x+nd

Average Method for one rational number between aa and bb: r=a+b2r = \frac{a + b}{2}

Condition for Terminating Decimal: pq\frac{p}{q} terminates if the prime factorization of qq is of the form 2nβ‹…5m2^n \cdot 5^m, where n,mn, m are non-negative integers.

πŸ’‘Examples

Problem 1:

Find five rational numbers between 11 and 22.

Solution:

Step 1: We want to find n=5n = 5 rational numbers. We use the denominator n+1=5+1=6n + 1 = 5 + 1 = 6.\nStep 2: Convert 11 and 22 into equivalent fractions with denominator 66.\n1=1Γ—66=661 = \frac{1 \times 6}{6} = \frac{6}{6}\n2=2Γ—66=1262 = \frac{2 \times 6}{6} = \frac{12}{6}\nStep 3: Identify five fractions between 66\frac{6}{6} and 126\frac{12}{6}.\nThese are 76,86,96,106,Β andΒ 116\frac{7}{6}, \frac{8}{6}, \frac{9}{6}, \frac{10}{6}, \text{ and } \frac{11}{6}.

Explanation:

To find nn numbers between two integers, we scale the integers into fractions with a denominator of n+1n+1. This creates nn equally spaced intervals between the original values.

Problem 2:

Show that 0.3333⋯=0.3‾0.3333\dots = 0.\overline{3} can be expressed in the form pq\frac{p}{q}, where pp and qq are integers and q≠0q \neq 0.

Solution:

Step 1: Let x=0.3333…x = 0.3333\dots (Equation 1)\nStep 2: Since one digit is repeating, multiply both sides by 101=1010^1 = 10.\n10x=3.3333…10x = 3.3333\dots (Equation 2)\nStep 3: Subtract Equation 1 from Equation 2.\n10xβˆ’x=(3.3333… )βˆ’(0.3333… )10x - x = (3.3333\dots) - (0.3333\dots)\n9x=39x = 3\nStep 4: Solve for xx.\nx=39=13x = \frac{3}{9} = \frac{1}{3}

Explanation:

By multiplying the repeating decimal by a power of 1010 corresponding to the length of the repeating block, we align the decimal parts so they cancel out during subtraction, leaving an integer equation.