krit.club logo

Coordinate Geometry - Plotting a Point in the Plane

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The Cartesian Plane is defined by two perpendicular number lines: the horizontal line called the xx-axis and the vertical line called the yy-axis. These lines intersect at a central point called the origin, denoted by O(0,0)O(0, 0).

The axes divide the plane into four distinct regions called Quadrants. Moving counter-clockwise from the top-right, they are: Quadrant I (+,+)(+, +), Quadrant II (,+)(-, +), Quadrant III (,)(-, -), and Quadrant IV (+,)(+, -). Visually, this looks like a cross dividing the space into four equal zones.

Every point in the plane is identified by an ordered pair (x,y)(x, y). The first value xx is the Abscissa (perpendicular distance from the yy-axis), and the second value yy is the Ordinate (perpendicular distance from the xx-axis).

To plot a point like P(x,y)P(x, y), you start at the origin (0,0)(0, 0). Move x|x| units along the xx-axis (right if x>0x > 0, left if x<0x < 0). Then, from that position, move y|y| units vertically (up if y>0y > 0, down if y<0y < 0).

Any point situated exactly on the xx-axis will have an ordinate of 00, resulting in the coordinate form (x,0)(x, 0). For example, (4,0)(4, 0) lies on the positive xx-axis.

Any point situated exactly on the yy-axis will have an abscissa of 00, resulting in the coordinate form (0,y)(0, y). For example, (0,5)(0, -5) lies on the negative yy-axis.

The distance of a point (x,y)(x, y) from the xx-axis is equal to y|y| units, and its distance from the yy-axis is equal to x|x| units.

📐Formulae

Coordinates of Origin=(0,0)\text{Coordinates of Origin} = (0, 0)

Point P=(x,y)\text{Point } P = (x, y)

Abscissa=x-coordinate\text{Abscissa} = x \text{-coordinate}

Ordinate=y-coordinate\text{Ordinate} = y \text{-coordinate}

Equation of x-axis:y=0\text{Equation of } x\text{-axis}: y = 0

Equation of y-axis:x=0\text{Equation of } y\text{-axis}: x = 0

💡Examples

Problem 1:

Identify the quadrant or axis for the following points: A(5,2)A(5, -2), B(0,3)B(0, 3), and C(4,7)C(-4, -7).

Solution:

  1. For A(5,2)A(5, -2), the xx-coordinate is positive and the yy-coordinate is negative. This corresponds to the (+,)(+, -) sign convention of Quadrant IV.
  2. For B(0,3)B(0, 3), the xx-coordinate is 00. Any point with x=0x = 0 lies on the yy-axis. Since y=3y=3 is positive, it lies on the positive yy-axis.
  3. For C(4,7)C(-4, -7), both xx and yy coordinates are negative. This corresponds to the (,)(- , -) sign convention of Quadrant III.

Explanation:

To determine the location, check the signs of the coordinates and compare them to the standard quadrant conventions or check if one coordinate is zero.

Problem 2:

Plot the point M(3,4)M(-3, 4) on the Cartesian plane and state its perpendicular distance from both axes.

Solution:

  1. To plot M(3,4)M(-3, 4), start at origin (0,0)(0, 0).
  2. Move 33 units to the left along the xx-axis to reach 3-3.
  3. From 3-3, move 44 units vertically upwards parallel to the yy-axis.
  4. Mark the point as M(3,4)M(-3, 4).
  5. The perpendicular distance from the xx-axis is the absolute value of the yy-coordinate: 4=4|4| = 4 units.
  6. The perpendicular distance from the yy-axis is the absolute value of the xx-coordinate: 3=3|-3| = 3 units.

Explanation:

Plotting involves directional movement based on signs. Distance is always a non-negative value, so we take the absolute value of the coordinates.