krit.club logo

Rational Numbers - Operations and Word Problems

Grade 8ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A rational number is any number that can be expressed in the form pq\frac{p}{q}, where pp and qq are integers and q0q \neq 0. Visually, rational numbers include all fractions, terminating decimals, and repeating decimals, appearing as distinct points between integers on a number line.

Addition and Subtraction of rational numbers require a common denominator. If denominators are different, find the Least Common Multiple (LCM). Visually, this process is like dividing different-sized segments on a number line into smaller, equal-sized units so they can be combined or compared accurately.

The product of two rational numbers is found by multiplying their numerators and their denominators separately: ab×cd=acbd\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}. Simplification can be done by 'cross-canceling' common factors between any numerator and any denominator before multiplying.

Division by a rational number is the same as multiplying by its reciprocal. The reciprocal of ab\frac{a}{b} is ba\frac{b}{a} (where a,b0a, b \neq 0). On a number line, dividing a length into nn parts is the same as multiplying that length by the unit fraction 1n\frac{1}{n}.

Additive and Multiplicative Identities: Zero (00) is the additive identity because adding it to any rational number does not change its value (x+0=xx + 0 = x). One (11) is the multiplicative identity because multiplying any rational number by it leaves the value unchanged (x×1=xx \times 1 = x).

Additive Inverse and Multiplicative Inverse: For every rational number ab\frac{a}{b}, there exists an additive inverse ab-\frac{a}{b} such that their sum is 00. The multiplicative inverse (or reciprocal) of ab\frac{a}{b} is ba\frac{b}{a}, such that their product is 11.

The Density Property states that between any two rational numbers, there are infinitely many other rational numbers. To find a rational number exactly halfway between two numbers xx and yy, use the formula x+y2\frac{x+y}{2}. This shows that the number line is 'dense' with rational points.

Distributive Property: For any three rational numbers a,b,a, b, and cc, the relationship a(b+c)=ab+aca(b + c) = ab + ac holds true. This property is vital for simplifying complex algebraic expressions and solving word problems involving shares or parts.

📐Formulae

Standard Form: pq,q0\text{Standard Form: } \frac{p}{q}, q \neq 0

Addition: ab+cd=ad+bcbd\text{Addition: } \frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}

Subtraction: abcd=adbcbd\text{Subtraction: } \frac{a}{b} - \frac{c}{d} = \frac{ad - bc}{bd}

Multiplication: ab×cd=a×cb×d\text{Multiplication: } \frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}

Division: ab÷cd=ab×dc\text{Division: } \frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

Additive Inverse: x+(x)=0\text{Additive Inverse: } x + (-x) = 0

Multiplicative Inverse: x×1x=1\text{Multiplicative Inverse: } x \times \frac{1}{x} = 1

Rational number between a and b=a+b2\text{Rational number between } a \text{ and } b = \frac{a + b}{2}

💡Examples

Problem 1:

Simplify the expression: 25(310)×56\frac{2}{5} - (\frac{-3}{10}) \times \frac{5}{6}

Solution:

Step 1: Following the BODMAS rule, perform the multiplication first. 310×56=3×510×6=1560=14\frac{-3}{10} \times \frac{5}{6} = \frac{-3 \times 5}{10 \times 6} = \frac{-15}{60} = \frac{-1}{4} Step 2: Substitute this back into the original expression: 25(14)=25+14\frac{2}{5} - (\frac{-1}{4}) = \frac{2}{5} + \frac{1}{4} Step 3: Find the LCM of 55 and 44, which is 2020. 2×45×4+1×54×5=820+520=1320\frac{2 \times 4}{5 \times 4} + \frac{1 \times 5}{4 \times 5} = \frac{8}{20} + \frac{5}{20} = \frac{13}{20}

Explanation:

We applied the order of operations (BODMAS), handling the multiplication of fractions by simplifying common factors first, and then solved the subtraction by converting it to addition of a positive fraction with a common denominator.

Problem 2:

A rope of length 101210\frac{1}{2} metres is cut into 77 equal pieces. What is the length of each piece?

Solution:

Step 1: Convert the mixed fraction to an improper fraction. Total length = 1012=(10×2)+12=21210\frac{1}{2} = \frac{(10 \times 2) + 1}{2} = \frac{21}{2} metres. Step 2: To find the length of each piece, divide the total length by the number of pieces. Length of each piece=212÷7\text{Length of each piece} = \frac{21}{2} \div 7 Step 3: Convert the division into multiplication by the reciprocal of 77. 212×17\frac{21}{2} \times \frac{1}{7} Step 4: Simplify the fractions. 21÷72×17÷7=32×1=32 or 112 metres\frac{21 \div 7}{2} \times \frac{1}{7 \div 7} = \frac{3}{2} \times 1 = \frac{3}{2} \text{ or } 1\frac{1}{2} \text{ metres}

Explanation:

This is a word problem involving division of rational numbers. We first express the total quantity as a fraction and then multiply by the reciprocal of the divisor to distribute the length equally.