Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Factorisation is the process of expressing an algebraic expression as a product of two or more expressions, called its factors. Visually, if an expression represents the area of a rectangle, factorisation is the process of finding the lengths of its sides.
The Method of Common Factors involves identifying the Highest Common Factor (HCF) of all the terms in an expression and then dividing each term by this HCF. Think of this as the 'reverse distributive law' where you move from to .
To find the HCF of monomials, find the HCF of the numerical coefficients and multiply it by each common variable raised to its lowest power. For example, in the terms and , the numerical HCF is , and the variable HCF is , making the total HCF .
When factorising by grouping, terms of an expression are arranged into groups such that each group has a common factor. This is often used when there is no single factor common to all terms. For example, in , the first two terms share and the last two share .
The sign of the common factor is crucial. If you extract a negative common factor, you must change the signs of all terms inside the brackets. For instance, becomes . Visually, this ensures that if you were to expand the brackets again, you would return to the original expression.
A common binomial factor can also be extracted. If an expression looks like , the entire bracket is treated as a single common factor, resulting in . This looks like two rectangular blocks sharing a common side length placed side by side.
📐Formulae
(Distributive Law in reverse)
(Grouping method)
💡Examples
Problem 1:
Factorise the expression:
Solution:
Step 1: Find the HCF of the numerical coefficients and . The HCF is .\Step 2: Find the HCF of the literal (variable) parts. For and , the HCF is . For and , the HCF is .\Step 3: Combine them to get the overall HCF, which is .\Step 4: Divide each term of the expression by the HCF: \ and .\Step 5: Write the expression as the product of the HCF and the remaining terms: .
Explanation:
This solution uses the basic method of identifying the HCF of coefficients and variables separately before combining them to factor out the expression.
Problem 2:
Factorise by grouping:
Solution:
Step 1: Rearrange the terms if necessary to find common factors. Let's group the first two and last two: .\Step 2: In the first group , the common factor is , so it remains .\Step 3: In the second group , the common factor is . Taking it out gives .\Step 4: Notice that and are opposites. Rewrite as .\Step 5: The expression becomes .\Step 6: Now, is a common binomial factor. Take it out to get .
Explanation:
This example demonstrates how to group terms and handle sign changes when the binomial factors are additive inverses of each other.