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Data Handling - Introduction to Probability

Grade 8ICSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A Random Experiment is a process where the result cannot be predicted with certainty. For example, tossing a coin is an experiment where you can see two possible outcomes: Heads or Tails. Visually, this is represented by the two distinct sides of the coin.

The Sample Space is the set of all possible outcomes of an experiment, denoted by SS. Visually, if you roll a six-sided die, the sample space is S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}, which can be visualized as the six numbered faces of a cube.

An Event is a specific outcome or a subset of the sample space. For instance, when rolling a die, 'getting an even number' is an event E={2,4,6}E = \{2, 4, 6\}. You can visualize this as selecting specific elements from the total set of outcomes.

Equally Likely Outcomes occur when each result in the sample space has the same chance of happening. For a fair die, each face from 11 to 66 is physically identical in size and weight, ensuring no face is favored over another.

Probability is a numerical value that ranges from 00 to 11, describing how likely an event is to occur. On a visual probability scale (a horizontal number line), 00 indicates an 'Impossible Event' at the far left, 11 indicates a 'Sure Event' at the far right, and 0.50.5 represents an 'Even Chance' in the exact center.

Complementary Events are two outcomes that are the only possibilities and whose probabilities sum to 11. If EE is the event of 'it raining', then 'it not raining' is the complement, denoted as E\overline{E}. Together, they cover the entire visual area of the sample space.

An Impossible Event has a probability of 00 because it can never happen, such as drawing a blue marble from a bag containing only red marbles. A Sure Event has a probability of 11 because it is certain to happen, like rolling a number less than 77 on a standard die.

📐Formulae

P(E)=Number of favorable outcomesTotal number of possible outcomesP(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}

0P(E)10 \le P(E) \le 1

P(E)+P(E)=1P(E) + P(\overline{E}) = 1

P(Sure Event)=1P(\text{Sure Event}) = 1

P(Impossible Event)=0P(\text{Impossible Event}) = 0

💡Examples

Problem 1:

A box contains 44 red, 55 green, and 1111 blue markers. If a marker is picked at random, find the probability that it is (i) a red marker and (ii) not a blue marker.

Solution:

  1. Total number of markers (Total outcomes) = 4+5+11=204 + 5 + 11 = 20. 2. (i) Favorable outcomes for Red = 44. Thus, P(Red)=420=15P(\text{Red}) = \frac{4}{20} = \frac{1}{5}. 3. (ii) Favorable outcomes for 'Not Blue' = Red + Green = 4+5=94 + 5 = 9. Thus, P(Not Blue)=920P(\text{Not Blue}) = \frac{9}{20}.

Explanation:

First, calculate the total sample space by summing all items. To find the probability of red, divide the red count by the total. To find the probability of 'not blue', add the counts of all markers that are not blue and divide by the total.

Problem 2:

A fair six-sided die is rolled. What is the probability of getting a prime number?

Solution:

  1. The total sample space S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}, so the total outcomes n(S)=6n(S) = 6. 2. The prime numbers on a die are 2,3, and 52, 3, \text{ and } 5. So, the favorable outcomes E={2,3,5}E = \{2, 3, 5\} and n(E)=3n(E) = 3. 3. P(Prime)=n(E)n(S)=36P(\text{Prime}) = \frac{n(E)}{n(S)} = \frac{3}{6}. 4. Simplifying the fraction gives P(Prime)=12P(\text{Prime}) = \frac{1}{2}.

Explanation:

Identify all possible results on the die faces. Then, list the prime numbers (numbers with exactly two factors) within that range. The ratio of prime outcomes to total outcomes provides the answer.